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Kryger [21]
2 years ago
14

if A and B together can do a piece of work in 10 days and B along can do it in 15 days, how many part of the work does A complet

e in 6 days ​
Mathematics
1 answer:
anzhelika [568]2 years ago
8 0

Answer:

1/5

Step-by-step explanation:

Well work can be defined as: work = rate \ *\ time

where rate=amount of work that can be done in one unit of time

let a = rate of work A does in a day

let b = rate of work B does in a day

this means that: 10a + 10b=1 where work=1 and it just means the entire job has been completed.

Since b can do it alone in 15 days, this means that: 15b=1

If we divide by 15 here, we get the equation: b=\frac{1}{15}

We can now use this definition to substitute it into the first equation we made.

10a + 10(\frac{1}{15}) = 1

Multiply the 10 and 1/15

10a+\frac{2}{3}=1

subtract 2/3 from both sides

10a=\frac{1}{3}

Now divide both sides by 10

a=\frac{1}{30}

Now multiply this by 6, since we a represents the amount of work that can be done in a day, we want to find how many parts of the work can be done by a in 6 days

6a=\frac{6}{30}

Now divide both the numerator and denominator by 6

a=\frac{1}{5}

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lorasvet [3.4K]

Answer:

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Step-by-step explanation:

let the number = X

If 139 is added, it becomes= X +139

the result becomes 44less than four time the number

= 4(39)-44 = 156-44 =112

the set up equation becomes

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solving for the value of X

X = 112-39

X = 73

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Bad White [126]
12 glad I could help!
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Can anyone help me out on this
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