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Kryger [21]
2 years ago
14

if A and B together can do a piece of work in 10 days and B along can do it in 15 days, how many part of the work does A complet

e in 6 days ​
Mathematics
1 answer:
anzhelika [568]2 years ago
8 0

Answer:

1/5

Step-by-step explanation:

Well work can be defined as: work = rate \ *\ time

where rate=amount of work that can be done in one unit of time

let a = rate of work A does in a day

let b = rate of work B does in a day

this means that: 10a + 10b=1 where work=1 and it just means the entire job has been completed.

Since b can do it alone in 15 days, this means that: 15b=1

If we divide by 15 here, we get the equation: b=\frac{1}{15}

We can now use this definition to substitute it into the first equation we made.

10a + 10(\frac{1}{15}) = 1

Multiply the 10 and 1/15

10a+\frac{2}{3}=1

subtract 2/3 from both sides

10a=\frac{1}{3}

Now divide both sides by 10

a=\frac{1}{30}

Now multiply this by 6, since we a represents the amount of work that can be done in a day, we want to find how many parts of the work can be done by a in 6 days

6a=\frac{6}{30}

Now divide both the numerator and denominator by 6

a=\frac{1}{5}

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umka21 [38]

4 1/2=4 2/4

4 2/4-1/4=4 1/4 or 4.25

8 0
3 years ago
A player of a video game is confronted with a series of opponents and has an 80% probability of defeating each one. Success with
Vikentia [17]

Answer:

(a) The PMF of <em>X</em> is: P(X=k)=(1-0.20)^{k-1}0.20;\  k=0, 1, 2, 3....

(b) The probability that a player defeats at least two opponents in a game is 0.64.

(c) The expected number of opponents contested in a game is 5.

(d) The probability that a player contests four or more opponents in a game is 0.512.

(e) The expected number of game plays until a player contests four or more opponents is 2.

Step-by-step explanation:

Let <em>X</em> = number of games played.

It is provided that the player continues to contest opponents until defeated.

(a)

The random variable <em>X</em> follows a Geometric distribution.

The probability mass function of <em>X</em> is:

P(X=k)=(1-p)^{k-1}p;\ p>0, k=0, 1, 2, 3....

It is provided that the player has a probability of 0.80 to defeat each opponent. This implies that there is 0.20 probability that the player will be defeated by each opponent.

Then the PMF of <em>X</em> is:

P(X=k)=(1-0.20)^{k-1}0.20;\  k=0, 1, 2, 3....

(b)

Compute the probability that a player defeats at least two opponents in a game as follows:

P (X ≥ 2) = 1 - P (X ≤ 2)

              = 1 - P (X = 1) - P (X = 2)

              =1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20\\=1-0.20-0.16\\=0.64

Thus, the probability that a player defeats at least two opponents in a game is 0.64.

(c)

The expected value of a Geometric distribution is given by,

E(X)=\frac{1}{p}

Compute the expected number of opponents contested in a game as follows:

E(X)=\frac{1}{p}=\frac{1}{0.20}=5

Thus, the expected number of opponents contested in a game is 5.

(d)

Compute the probability that a player contests four or more opponents in a game as follows:

P (X ≥ 4) = 1 - P (X ≤ 3)

              = 1 - P (X = 1) - P (X = 2) - P (X = 3)

              =1-(1-0.20)^{1-1}0.20-(1-0.20)^{2-1}0.20-(1-0.20)^{3-1}0.20\\=1-0.20-0.16-0.128\\=0.512

Thus, the probability that a player contests four or more opponents in a game is 0.512.

(e)

Compute the expected number of game plays until a player contests four or more opponents as follows:

E(X\geq 4)=\frac{1}{P(X\geq 4)}=\frac{1}{0.512}=1.953125\approx 2

Thus, the expected number of game plays until a player contests four or more opponents is 2.

4 0
3 years ago
What is the solution to the equation 7^3x ≈ 9 ?
egoroff_w [7]
7^{3x}\approx9\\\\\log_77^{3x}\approx\log_79\\\\3x\approx\log_79\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x\approx\dfrac{\log_79}{3}=\frac{1}{3}\log_79=\log_79^\frac{1}{3}=\log_7\sqrt[3]9}
7 0
4 years ago
Solve the radical equation x – 7 = square root of -4x+28. Which statement is true about the solutions to the radical equation? T
Julli [10]

Answer:

x = 3 and 7

There are two true solutions.

Step-by-step explanation:

To solve x-7 = \sqrt{-4x+28}, use inverse operations by squaring both sides of the equal sign.

(x-7)^2 = (\sqrt{-4x+28})^2\\x^2-14x+49 = -4x+28\\x^2-14x+4x+49-28 = 0\\x^2-10x+21=0

The quadratic expression can be factored into binomials and set equal to 0 by the zero product property to find x.

(x - 3) ( x - 7) = 0

x-3 = 0 so x=3

x-7 = 0 so x=7

Now check each solution into the original equation to be sure it solve the solution and is not extraneous.

7-7 = \sqrt{-4(7)+28}\\ 0=0

and

3-7 = \sqrt{-4(3)+28}\\[tex]-4 = \sqrt{16}\\-4 =-4[/tex]

3 0
3 years ago
Given h of x equals negative 2 times the square root of x minus 3 end root, which of the following statements describes h(x)?
Yuliya22 [10]

Using translation concepts, it is found that the correct option regarding the function is:

The function h(x) is decreasing on the interval (3, ∞).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The parent function is given by:

f(x) = \sqrt{x}

Which increases on (0, ∞).

The translated function is given by:

g(x) = -2\sqrt{x - 3}

With the translation, the domain is now (-3, ∞), and the function is decreasing, hence the correct option is given by:

The function h(x) is decreasing on the interval (3, ∞).

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

8 0
2 years ago
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