Answer:
Total number of bracelets Brianna have are 12 .
Step-by-step explanation:
Let us assume that the total numbers of the bracelets be x .
As given
Brianna has 4 pink bracelets.
One third of all her bracelets are pink .
Than the equation becomes

Simplify the above
x = 4 × 3
x = 12
Therefore the total number of bracelets Brianna have are 12 .
Answer:
1144 o 286
Step-by-step explanation:
Si pregunta por la cantidad de personas que se pesaron, la respuesta es (8/10) * (1430) = 8 * 143 = 1144.
Si desea saber cuántas personas no se pesaron, la respuesta es 1430* (2/10) = 286
Answer:
a
The probability that the selected joint was judged to be defective by neither of the two inspectors is 
b
The probability that the selected joint was judged to be defective by inspector B but not by inspector A is 
Step-by-step explanation:
From the question we are told that
The sample size is 
The number of outcome for inspector A is 
The number of outcome for inspector B is 
The number of joints judged defective by both inspector is 
The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

Now

substituting values

So


the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

Now

substituting values

So


Use PEMDAS with the first 3.
a. 3×(6÷5)
3×(1.2) [Parenthesis first]
3.6. [then multiply]
b. 3÷(5×6)
3÷(30) [Parenthesis first]
.1 [then divide]
c. (3×6)÷5
(18)÷5 [Parenthesis first]
3.6 [then divide]
d. 3×6÷5
18÷5 [Left to right]
3.6 [then divide]