The distance<u> between </u>Jays hair and the caffe shop is 2.5 km.
Since the mall is located 2.4 kilometers<u> north</u> of jays house and the caffe shop is located 0.7 kilometers <u>east </u>of the mall, both directions are perpendicular. So, the distance between Jays hair and the caffe shop forms the hypotenuse side of this right angled triangle.
So, using Pythagoras' theorem, we find the hypotenuse side of this triangle, L.
Pythagoras' theorem states that the sum of squares of the sides of a right angled triangle equal the square of the hypotenuse side.
So, L = √[(2.4 km)² + (0.7 km)²]
L = √[(5.76 km² + 0.49 km²]
L = √(6.25 km²)
L = 2.5 km
So, the distance<u> between </u>Jays hair and the caffe shop is 2.5 km.
Learn more about Pythagoras' theorem here:
brainly.com/question/8171420
Answer:
Step-by-step explanation:
Given that the solution of a certain differential equation is of the form
![y(t) = ae^{7t} +be^{11t}](https://tex.z-dn.net/?f=y%28t%29%20%3D%20ae%5E%7B7t%7D%20%2Bbe%5E%7B11t%7D)
Use the initial conditions
i) y(0) =1
... I
ii) y'(0) = 4
Find derivative of y first and then substitute
![y'(t) = 7ae^{7t} +11be^{11t}\\y'(0) =7a+11b \\7a+11b =4 ...II](https://tex.z-dn.net/?f=y%27%28t%29%20%3D%207ae%5E%7B7t%7D%20%2B11be%5E%7B11t%7D%5C%5Cy%27%280%29%20%3D7a%2B11b%20%5C%5C7a%2B11b%20%3D4%20...II)
Now using I and II we solve for a and b
Substitute b = 1-a in II
![7a+11(1-a) = 4\\-4a+11 =4\\-4a =-7\\a = 1.75 \\b = -0.75](https://tex.z-dn.net/?f=7a%2B11%281-a%29%20%3D%204%5C%5C-4a%2B11%20%3D4%5C%5C-4a%20%3D-7%5C%5Ca%20%3D%201.75%20%5C%5Cb%20%3D%20-0.75)
Hence solution is
![y(t) = 1.75e^{7t} -0.75e^{11t}](https://tex.z-dn.net/?f=y%28t%29%20%3D%201.75e%5E%7B7t%7D%20-0.75e%5E%7B11t%7D)
Answer:
The volume of the dilated prism is
.
Step-by-step explanation:
The original prism has base area
and a height of
.
The volume of the original prism is
.
The prism is dilated by a scale factor of
.
To find the volume of the dilated prism, we multiply the volume of the original prism by
.
![V=\frac{216}{125} \times 50ft^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B216%7D%7B125%7D%20%5Ctimes%2050ft%5E3)
![\Rightarrow V=86.4ft^3](https://tex.z-dn.net/?f=%5CRightarrow%20V%3D86.4ft%5E3)
100/20=5
11×5=55
11/20 = 0.55