Answer:
the correct answer to your question would be option c
During the birthday 4/7 of the cake was eaten so it remained 1-4/7=3/7
the next day 1/2 of 3/7 was eaten what remained is 3/7 divide by 1/2
to divide we invert the second fraction (1/2) and multiply 3/7
3/7 x 2/1=6/7
<em>x</em> kg of Maxwell House coffee contains 0.13<em>x</em> kg of Columbian beans.
<em>y</em> kg of Folgers contains 0.21<em>y</em> kg of beans.
You want a mixture weighing 70 kg, so
<em>x</em> + <em>y</em> = 70
You also want this blend to consist of 19% Columbian beans, or 0.19 (70 kg) = 13.3 kg, so
0.13<em>x</em> + 0.21<em>y</em> = 13.3
Solve for <em>x</em> and <em>y</em> :
<em>x</em> + <em>y</em> = 70 ===> <em>y</em> = 70 - <em>x</em>
0.13<em>x</em> + 0.21<em>y</em> = 13.3 ===> 0.13<em>x</em> + 0.21 (70 - <em>x</em>) = 13.3
0.13<em>x</em> + 14.7 - 0.21<em>x</em> = 13.3
14.7 - 13.3 = 0.21<em>x</em> - 0.13<em>x</em>
1.4 = 0.08<em>x</em>
<em>x</em> = 17.5
<em>y</em> = 52.5
Answer:
Hopefully, the problem is worded as follows:
a after 3 years = A (1.08)^3 = 1.2597 A after 3 years (invested at end of year)
a after 2 years = A (1.08)^2 = 1.1664 A after 2 years
a after 1 year = A (1.08) = 1.08 A
a last year = A
adding the columns
4 a = 4.5061 A where A is the amount invested each year and a is the total worth of such an investment
or a = 1.12653 A
A = a / 1.12653 = 550,000 / 1.12653 = 488,226 for the total investment
Each year 488,226 / 4 must be invested = 122,057
