Answer:
7:12
Step-by-step explanation:
Total no of animals in the field = 7 + 5 = 12
Ratio of cows 2 all d animals in the field =

Ratio = 7/12 = 7:12
Answer:
Step-by-step explanation:
Given that:
The differential equation; 
The above equation can be better expressed as:

The pattern of the normalized differential equation can be represented as:
y'' + p(x)y' + q(x) y = 0
This implies that:



Also;


From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2
When x = - 2






Hence, one (1) of them is non-analytical at x = 2.
Thus, x = 2 is an irregular singular point.
Answer:
m<1 = 105°
m<2 = 75°
very simple explanation:
a and b are perpendicular. line t intersects these perpendicular lines. the given 75° is, in short, an intersect of a line, which is 180°. 75-180=105. angles 1 and 2 are duplicates of what is shown
Discriminant = square root (b^2 -4*a*c)
square root (64 -4*1*12) =
square root (16) =
4
Therefore it has 2 rational soltions