The correct answer is option D which is the side length will be (64n)¹⁸.
<h3>What is the area of the square?</h3>
The square is defined as a quadrilateral having all four sides equal to each other and the area of the square is the product of its sides.
Given that:-
- The area of the square is given as- A = (64n)³⁶.
The sides of the square will be calculated as follows:-
A = (64n)³⁶
a² = (64n)³⁶ Here a = Side of the square.
a = √ (64n)³⁶
a = 64n¹⁸
Therefore the correct answer is option D which is the side length will be (64n)¹⁸.
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The circle equation is in the format (x – h)² + (y – k)² = r², with the center being at the point (h, k) and the radius being "r".
QUESTION 11.
Equation x²+y²+10x-14y-7 =0 can be rewritten as: x²+10x+25 + y² -14y + 49 -7 - 25 - 49=0
It can be factories as (x + 5)² + (y – 7)² = 9²
Therefore the radius equals 9 and the center is (-5,7)
QUESTION 12.
From equation (x + 4)² + y² = 121
The radius equals √121 = 11 and the center is (-4,0)
QUESTION 13.
As there are missing information in the question, I can't assist. However, you can use the general circle equation (x – h)² + (y – k)² = r² to solve the question.
Finally equations 14 & 15 aren't linear.
Hope that helps you :)
Answer:
The Answer is: 75.
Step-by-step explanation:
Set up the equation:
45 / 600 = y / 1000
600y = 45 * 1000
600y = 45000
y = 45,000 / 600 = 75.
Answer:
b
Step-by-step explanation:
you can break the 78 into 70 and 8, and multiply them separately by 6 and then add the two answers to get 468
<span>As the age of the U-235 sample is 2.631 billion years, and the half-life of U-235 is 713 million years, the sample has undergone 2.361 X 1,000,000,000 / 713 X 1,000,000 = 3.69 half lives. In each half-life the sample reduces to half its original weight according to the radioactive Half-Life Formula:
ln (Nt /N0) = -kt, where N0 = mass of the original weight of radioactive material, Nt = mass of radioactive material at time t, k = decay constant and t = time interval . We have to put Nt/N0 = 1/2 for time interval = half-life.</span>
