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3 years ago

Please help!!

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

8 0

I think the answer would be C.

LiRa [457]3 years ago

8 0

Answer:

its C

Step-by-step explanation:

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Write declaration statements to declare and initialize two variables: one is an integer variable named age, initialized to 18, a

Fantom [35]

In Java....

int age=18;

float weight=114.5;

8 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

What is the completely factored form of f(x) = 6x3 – 13x2 – 4x + 15?

masya89 [10]

We have to determine the complete factored form of the given polynomial

$f(x)=6x^3-13x^2-4x+15$ .

Let x= -1 in the given polynomial.

So, $f(-1)= 6(-1)^3-13(-1)^2-4(-1)+15 = -6-13+4+15 = 0$

So, by factor theorem

(x+1) is a factor of the given polynomial.

So, dividing the given polynomial by (x+1), we get quotient as $6x^2-19x+15$ .

So, $6x^3-13x^2-4x+15$ = (x+1) $6x^2-19x+15$ .

= $(x+1)(6x^2-10x-9x+15)$

= $(x+1)[ 2x(3x-5)-3(3x-5)]$

= $(x+1)(2x-3)(3x-5)$ is the completely factored form of the given polynomial.

Option D is the correct answer.

5 0

3 years ago

Read 2 more answers

X = 8,1,3,3,5

Ghella [55]

Answer:

2.600 = Exact

2.6 = Base Form

Step-by-step explanation:

6 0

2 years ago

10x + 9y=0<br> 8x + 18y=0

Luba_88 [7]

Answer:

x=0 y=0

Step-by-step explanation:

multiple the first equation by 2

after subtract equation 2 from 1

after getting x you substitute the value of x in any of the equation for your y

3 0

3 years ago