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2 years ago

Find the cosine of ∠J.

1 answer:

5 0

Answer:

$\cos = \frac{base}{hypotenuse} = \\ \cos(j) = \frac{ \sqrt{29} }{ \sqrt{94} } = \sqrt{ \frac{29}{94} } \\ answer = \sqrt{ \frac{29}{94} }$

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ankoles [38]

<h2>Answer:</h2>

$\boxed{\overline{MN}=37.96}$

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find $\overline{MN}$ . Since:

$\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm$

and $\overline{MN}$ is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

$\overline{RN}=\overline{QN}$

By Pythagorean theorem, for triangle NQP:

$\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}$

Applying Pythagorean theorem again, but for triangle MQN:

$\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}$

3 0

3 years ago

kobusy [5.1K]

X/35 = 100...multiply both sides by 35
x = 100 * 35
x = 3500

7 0

3 years ago

masha68 [24]

The of is essentially the multiplication operator hence

$89\%\cdot355=0.89\cdot355=315.95$

Hope this helps.

8 0

3 years ago

goldfiish [28.3K]

The equation of the line through (-4, -5) parallel to 3x-4y=-8 can be written as
3(x-(-4)) - 4(y-(-5)) = 0
3x -4y - 8 = 0
3x - 4y = 8

4 0

3 years ago

aev [14]

2÷5=0.4l
0.4l×1000=400ml

7 0

3 years ago