This is the concept of algebra, we are required to calculate the area cut out of a cylinder represented by the function x^2+z^2=36;
The equation of a circle is given by:
(x-a)^2+(y-b)^2=r^2
where;
(a,b) are the center of the circle;
r=radius of the circle
re-writing our equation we have:
x^2+z^2=36
(x-0)^2+(z-0)^2=6^2
this implies that the center of the circle is (0,0) and the radius is 6 units;
Therefore the area will be given by:
Area=πr^2
Area=π*6^2
Area=36π=113.1 sq. units
Y = a(x - h)² + k • (h, k) is the vertex • x = h is line of symmetry so y = ax² - 2x - 3 y/a = x² - 2/ax - 3/a y/a + 3/a = x² - 2/ax y/a + 4/a= x² - 2/ax + (-1/a)² ← completing the square y/a + 4/a= (x - 1/a)² y/a = (x - 1/a)² - 4/a y = a(x - 1/a)² - 4 so since you've been given h = 1 then 1/a = 1 and so a = 1
Answer:
90
Step-by-step explanation:
for percentage
×100
= 0.9×100
=90
Answer:
Acute triangle
x = 3
GH = 19
Step-by-step explanation:
