The graph is shown in figure below
The Solution Set is (-2,-3)
Step-by-step explanation:
We need to graph the equations and writ the solution.
For graphing we need to find the values of x and y.
For that, we need to solve the given equations:

Let:

We can solve this by using Substitution Method.
Putting value of y of eq(1) into eq(2) and finding value of x:

So, value of x = -2
Now put value of x in eq(1) to find value of y:

So, value of y = -3
Plotting on graph: x=-2 and y = -3
The graph is shown in figure below
The Solution Set is (-2,-3)
Keywords: graph the equations
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Answer:
the answer is D. I just took the exam.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Choose a random fraction less than 1. I will choose 1/4.
1/6 ÷ 1/4 = 1/6 × 4/1 = 4/6 = 2/3
2/3 > 1/6 so this example supports his claim.
Now chose a fraction greater than 1. I will choose 4/3
1/6 ÷ 4/3 = 1/6 * 3/4 = 3/24
3/24 < 1/6 so this contradicts his claim
Answer:
1) (x + 3)(3x + 2)
2) x= +/-root6 - 1 by 5
Step-by-step explanation:
3x^2 + 11x + 6 = 0 (mid-term break)
using mid-term break
3x^2 + 9x + 2x + 6 = 0
factor out 3x from first pair and +2 from the second pair
3x(x + 3) + 2(x + 3)
factor out x+3
(x + 3)(3x + 2)
5x^2 + 2x = 1 (completing squares)
rearrange the equation
5x^2 + 2x - 1 = 0
divide both sides by 5 to cancel out the 5 of first term
5x^2/5 + 2x/5 - 1/5 = 0/5
x^2 + 2x/5 - 1/5 = 0
rearranging the equation to gain a+b=c form
x^2 + 2x/5 = 1/5
adding (1/5)^2 on both sides
x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2
(x + 1/5)^2 = 1/5 + 1/25
(x + 1/5)^2 = 5 + 1 by 25
(x + 1/5)^2 = 6/25
taking square root on both sides
root(x + 1/5)^2 = +/- root(6/25)
x + 1/5 = +/- root6 /5
shifting 1/5 on the other side
x = +/- root6 /5 - 1/5
x = +/- root6 - 1 by 5
x = + root6 - 1 by 5 or x= - root6 - 1 by 5
Answer/Step-by-step explanation:
Recall: 
a. 
b. 
c. 