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erastova [34]
4 years ago
7

Write the square of the binomial as a polynomial: (-1 1/3p + 6q)^2

Mathematics
1 answer:
Thepotemich [5.8K]4 years ago
5 0

Answer:

\frac{16}{9}p² -16pq + 36q²

Step-by-step explanation:

Given

(- \frac{4}{3}p + 6q)²

= (- \frac{4}{3}p + 6q)(- \frac{4}{3}p + 6q)

Each term in the second factor is multiplied by each term in the first factor, that is

- \frac{4}{3}p(- \frac{4}{3}p + 6q) + 6q(- \frac{4}{3}p + 6q)

= \frac{16}{9}p² - 8pq - 8pq + 36q² ← collect like terms

= \frac{16}{9}p² - 16pq + 36q²

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How do you find the missing number of a perfect square trinomial?<br><br> 25x^2 - 60x + ___
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Answer:

  36

Step-by-step explanation:

Compare what you have to the square ...

  (a +b)^2 = a^2 +2ab +b^2

Your "a" is √(25x^2) = 5x

Your "2ab" is -60x. Since you know "a", you can find "b".

  2ab = -60x

  2(5x)b = -60x . . . . . . . substitute for "a"

  b = -60x/(10x) = -6

Then the missing term is b^2 = (-6)^2 = 36.

Your trinomial is ...

  25x^2 -60x +<u>36</u>

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Find the x-values for which f(x) = g(x)<br> if you know that f(x) = x2 and g(x) = 2x.
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For this case we have the following functions:

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ANswer:

The values of x for which f (x) = g (x)are 0 and 2.

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