Answer:
100r^4 + 400r^3 + 600r^2 + 400r + 100
Step-by-step explanation:
Expanding ( r + 1 )^4 gives :-
r^4 + 4r^3 + 6r^2 + 4r + 1
So multiplying 100 with r^4 + 4r^3 + 6r^2 + 4r + 1 gives :-
100r^4 + 400r^3 + 600r^2 + 400r + 100
Answer:
8/3
Step-by-step explanation:
i put equations as this:
x+40 = y
where x is galllons of pure mixture and y is the gallons of the new mixture
the other equation i id was:
x+0.2(40) = 0.25y
x+8 = 0.25y
y = 4x+32
solve using substitution
(x+40) = 4x+32
x = 4x-8
-3x = -8
x = 8/3
Answer:
En el curso anterior había 430 alumnos.
Step-by-step explanation:
El curso tiene 473 alumnos. Nos dicen que respecto al curso anterior se ha producido un aumento de inscripciones del 10 %. Entonces, siendo x la cantidad de alumnos que había en el curso anterior, se puede plantear la ecuación:
x + 0.1*x= 473
Resolviendo se obtiene:
1.1*x=473
x= 473 ÷1.1
x= 430
<u><em>En el curso anterior había 430 alumnos.</em></u>
I believe the answer is 28.18
Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
