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3 years ago

Which relation is a function

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

$\{(\boxed{2};\ 3);\ (1;\ 5);\ (\boxed{2};\ 7)\}-NO\\\\\{(-1;\ 5);\ (-2;\ 6);\ (-3;\ 7)\}-YES\\\\\{(\boxed{11};\ 9);\ (\boxed{11};\ 5);\ (9;\ 3)\}-NO\\\\\{(\boxed{3};\ 8);\ (0;\ 8);\ (\boxed{3};\ -2)\}-NO$

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Suppose you take $25,000 and deposit some of it into a savings account that pays 2.2% interest. You then take the rest of the mo

FromTheMoon [43]

Answer:

The amount deposited in the savings account is $11,494.12

The amount deposited in the CD account is $13,505.88

Step-by-step explanation:

Firstly, let’s calculate the amount of interest;

Interest = Amount at end of 10 years - amount deposited= 31,648 -25,000 = 6,648

Let the amount deposited in the savings account be $x while the amount deposited in the CD account be $y

Mathematically;

x + y = 25,000 ••••••••••(i)

Now the formula for simple interest is;

PRT/100

where P is the amount deposited, r is the rate and T is the time

On the savings account, amount of interest generated will be;

(x * 2.2 * 10)/100 = 22x/100

On the CD act, amount of interest generated will be;

(y * 3.05 * 10)/100 = 30.5y/100

The addition of both give the total interest;

22x/100 + 30.5y/100 = 6648

Multiply through by 100

22x + 30.5y = 664800 •••••••(ii)

From i, x = 25,000 - y

Substitute this into ii

22(25000-y) + 30.5y = 664800

550,000 -22y + 30.5y = 664,800

8.5y = 664,800-550,000

8.5y = 114,800

y = 114,800/8.5

y = $13,505.88

x = 25,000 -y

x = 25,000 - 13,505.88

x = $11,494.12

3 0

3 years ago

Can someone help me I taking a test right now no links please

Allisa [31]

I think the answer is 12

8 0

2 years ago

two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe

sveta [45]

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

$hyp^{2}$ = $adj 1^{2}$ + $adj 2^{2}$