Consider the triangles below. Which statement is true?

Mathematics

1 answer:

Zanzabum2 years ago

6 0

Answer:

Step-by-step explanation:

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Solve the system using the addition method. State your solution as an ordered pair.

vladimir1956 [14]

Solution as ordered pair is:

(5, $\frac{41}{2}$ )

Step-by-step explanation:

Solving the system of equations:

$3x+2y=56\,\,\,(1)\\9x-2y=4\,\,\,(2)$

Adding equation(1) and equation(2)

$3x+2y=56\\9x-2y=4\\--------\\12x=60\\x=\frac{60}{12}\\x=5$

Putting value of x i.e x=5 in equation(1)

$3x+2y=56\\3(5)+2y=56\\ 15+2y=56\\2y=56-15\\2y=41\\y=\frac{41}{2}\\y=\frac{41}{2}$

So, value of x=5 and y= $\frac{41}{2}$

Solution as ordered pair is:

(5, $\frac{41}{2}$ )

Keywords:System of Equations

Learn more about System of Equations at:

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6 0

3 years ago

Is m=10 and m=-10 is it parallel lines or perpendicular

MakcuM [25]

Neither, for lines to be parallel they have to have the same slope, and for lines to be perpendicular they have to be the negative reciprocal of the slope of the other line. In this case, the line perpendicular to the line with slope m=10 would be m=1/-10 or -1/10

7 0

2 years ago

Evaluate the limit, if it exists. (if an answer does not exist, enter dne.) lim h → 0 (−6 + h)2 − 36 h

Lyrx [107]

The limit can be found by simplifying the expression.
$\lim\limits_{h\rightarrow 0}\left(\dfrac{(-6+h)^{2}-36}{h}\right)=\lim\limits_{h\rightarrow 0}\left(\dfrac{-12h+h^{2}}{h}\right)\\\\=\lim\limits_{h\rightarrow 0}(-12+h)\\\\=-12$

The limit is -12.