Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
trufe
Step-by-step explanation:
Answer:
191
Step-by-step explanation:
Sorry it's sideways. I drew a box chart for this. First, fill in what you know: the number of white and black beads Ally has. Then, calculate how many black beads Betty has (Ally's number, 59, minus 35.) 59-35 = 24.
They tell you the total number of beads is 346. Add up Ally's total to get 131, then subtract that from 346. That's Betty's total beads, 215.
Last, subtract the 24 black beads Betty has from the 215 total to get 191.
Answer:
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Step-by-step explanation:
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