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3 years ago

What is 8.75 times 37.5

Mathematics

2 answers:

fomenos3 years ago

5 0

328.125 this is the answer because when you multiply 8.75 by 37.5 you will get that answer.

Y_Kistochka [10]3 years ago

4 0

  8. 75
* 37. 5
4375
   + 6125
2625
328125

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One of the psychologist's findings is that 18 months after the workshop, a sample of 49 job seekers who received training on set

IceJOKER [234]

Answer:

The psychologist finds that the estimated Cohen's d is 0.583.

Step-by-step explanation:

The Cohen's d is used to calculate the effect size, appied when a null hypothesis is rejected.

It can be calculated for this case of population mean as:

$d=\dfrac{M-\mu}{\sigma}=\dfrac{6.5-5.8}{1.2}=\dfrac{0.7}{1.2}=0.583$

The psychologist finds that the estimated Cohen's d is 0.583.

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4 years ago

The number of fish and a leg decreased by 25% between last year and this year. Last year there were 60 fish in the lake. What is

Elena-2011 [213]

Answer:

Step-by-step explanation:At the start of the question the population of the lake was 60 fish 1 year ago.

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25% of 60 is 15.

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4 years ago

gavin has 460 baseball players in his collection of baseball cards and 15% of the players are pitchers.how many pitchers are in

Kruka [31]

69 is the correct answer

460 divided by 100 times 15 = 69

8 0

3 years ago

I WILL MARK BRAINIEST!!!

cricket20 [7]

Answer:

-3

Step-by-step explanation:

First you subtract the first equation from the second one and you get:

3x + 3y = 3

x + y = 1

y = 1 - x

Then you use it on the first equation

888x + 889 (1 - x) = 890

888x + 889 - 889x = 890

-x = 1

x = -1

y = 1 - x

y = 1 - (-1) = 2

Now that you have those two numbers, we have to subtract the value of x from y:

x - y

-1 - 2 = -3

Hope this helps bro

6 0

3 years ago

On a normally distributed anxiety test with mean 48 and standard deviation 4, approximately what anxiety test score would put so

lbvjy [14]

Answer:

54.56

Step-by-step explanation:

Given:

Mean, u = 48

Standard deviation, $\sigma$ = 4

Test score = 5%

Required:

Find the raw score, X.

Having a test score of 5% means the Zscore has to correspond to 95%, ie, 1 - 0.05 = 0.95.

Thus, $Z_0_._9_5 = 1.64$

To get X, use the formula:

$mu + z * \sigma$

= 48 + (4 * 1.64)

= 48 + 6.56

= 54.56

The anxiety test score that would put someone in the top 5% is 54.56

5 0

3 years ago