Slope = (y2 - y1) / (x2 - x1)
slope = (-7-10) / (5 - (-3)
slope is supposed to be -17/8
I am guessing she made her mistake by adding a negative sign...the student did : (-7 - (-10) / (5 - (-3) = (-7 + 10) / (5 + 3) = 3/8
Bro I’m rly sorry but I don’t know the answer to this
Answer:
The slope for the lines is 2/3
The polar coordinates are given by M(x, y), such tha x=rcos(teta), and y=rsin(teta), it was given M(5,5), so 5=rcos(teta) and 5=rsin(teta), the ratio gives us 5/5= cotan (teta), 1= cotan (teta), implies 1= tan(teta), so teta = Pi/4, let's find r
5=rsin(Pi/4)=r . sqrt(2)/2, so r =10/sqrt(2)=10sqrt(2)
finally the polar coordinates are (r, teta) = (10sqrt(2), Pi/4)
