Please answer this. please please please please

Mathematics

1 answer:

kvasek [131]3 years ago

7 0

The value of the expression will decrease as x increases.
You can test this out by plugging in random numbers in place of x, like 20-5=15 and 20-8=12. The value of the expression (or the answer) is becoming smaller as the value of x becomes larger.

Hope this helps :)

You might be interested in

85% as a fraction or mixed number

Sphinxa [80]

85/100 isnsvsisjdbbsbsjsjdjd

3 0

3 years ago

Read 2 more answers

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey

Lubov Fominskaja [6]

Answer:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

Step-by-step explanation:

For this case we have the following distribution given:

X 0 1 2 3 4 5 6

P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02

For this case we need to find first the expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And replacing we got:

$E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61$

Now we can find the second moment given by:

$E(X^2) =\sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97$

And the variance would be given by:

$Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779$

And the deviation would be:

$Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54$

8 0

3 years ago

In a fifth grade class, 4/5 of the girls have brown hair, of the brown-haired girls, 3/4

AfilCa [17]

Answer:

$\frac{3}{5}$

Step-by-step explanation:

In the fifth grade class, $\frac{4}{5}$ of the girls have brown hair. Again among those of the brown-haired girls, $\frac{3}{4}$ of them have long hair.