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2 years ago

Solve the equation. h + | -8| = 15

Mathematics

2 answers:

kozerog [31]2 years ago

6 0

Answer:

if you're trying to say h+ -8 = 15 then h would be 23

Hoochie [10]2 years ago

4 0

These || would mean the -8 is just 8 so it would be 15-8 which is 7

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What is the cofunction of cos 2pi/ 9

fiasKO [112]

The cofunction of cos is sin(90-x)

90 degrees is equal to PI/2

The cofunction becomes sin(PI/2 - 2PI/9)

Rewrite both fractions to have a common denominator:

PI/2 = 9PI/18

2PI/9 = 4PI/18

Now you have sin(9PI/18 - 4PI/18)

Simplify:

Sin(5PI/18)

3 0

2 years ago

Part B

Elza [17]

Answer:

copy and paste

Step-by-step explanation:

6 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

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3 years ago

Challenge An arts academy requires there to be 4 teachers for every 76 students and 3 tutors for

klio [65]

Answer:

12. 5

11.

15. 7

14. 11

18. 3

loo

Step-by-step explanation:

12. 5

11.

15. 7

14. 11

3 0

2 years ago

the bottom of a ladder must be placed 10 feet from a building. The ladder is 26 feet. How far above the ground does the ladder t

Sauron [17]

Answer:

<em>The ladder touches the wall at 24 feet from the ground.</em>

Step-by-step explanation:

The wall of the building, the ground, and the ladder form a right triangle, whose longer side is the length of the ladder.

In any right triangle, we can apply Pythagora's theorem to find any missing side length.

The ladder is 26 feet in length, the distance from the bottom of the ladder and the building is 10 feet. Calling H to the distance above the ground where the ladder touches the wall, then:

$26^2=10^2+H^2$

Calculating:

$676=100+H^2$

Solving:

$H^2=676-100$

$H^2=576$

$H=\sqrt{576}$

H=24 feet

The ladder touches the wall at 24 feet from the ground.

8 0

3 years ago