9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
If you apply the linear combination method to the system like:
<span>4(.25x + .5y = 3.75) → x + 2y = 15
(4x – 8y = 12) → x – 2y = 3
2x = 18
Then you can be sure that the solution of all this system is: (9,3). Hope this si what you were looking for</span>
I’m not to sure my my guess is zero because it is not going up or down
Answer:
x > −3
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
Step 2: Subtract 3 from both sides.
Step 3: Divide both sides by -3.
