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GrogVix [38]
3 years ago
5

Explain how to verify that 3(2x + 5) = 9 + 3x and x = –2 are equivalent equations.

Mathematics
1 answer:
aniked [119]3 years ago
6 0

3 times (2x + 5) is 6x + 15.

6x + 15 = 9 + 3x.

Group by like terms. 6 = -3x

Divide to get x by itself. 6/-3 = -2

Thus -2 = x

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3 years ago
Given that e= 2i – 5j + 9k and f= 8i + 15j + k, find 3f – 2e.
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Plug in "8i + 15j + k" for "f", and "2i – 5j + 9k" for "e"

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3(8i + 15j + k) = 24i + 45j + 3k

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(24i - 4i) + (45j + 10j) + (3k - 18k)

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3 years ago
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4 0
3 years ago
a line with slope 3 passes through point (0,10). What is the y-coordinate of the point on the line with x-coordinate 2
skad [1K]

The y-coordinate is 16

<h3><u>Solution:</u></h3>

Given that a line with slope 3 passes through point (0, 10)

To find the y-coordinate of the point on the line with x-coordinate 2

Which means the point is (2, y)

Let us find the required y co-ordinate using slope formula

<em><u>The slope of line is given as:</u></em>

For a line containing points (x_1 , y_1) and (x_2 , y_2) is given as:

\text {slope}=m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text {Here } x_{1}=0 ; y_{1}=10 ; x_{2}=2 ; y_{2}=y

Given that slope "m" = 3

Substituting the values we get,

\begin{array}{l}{3=\frac{y-10}{2-0}} \\\\ {3=\frac{y-10}{2}} \\\\ {6=y-10} \\\\ {y=10+6=16}\end{array}

Thus the y-coordinate is 16

8 0
3 years ago
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