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NARA [144]
3 years ago
7

Two thirds of a number is no more than -10

Mathematics
1 answer:
Aliun [14]3 years ago
7 0
Let x be the number in the problem. When it states that x is "no more than -10", it means than it is less than or equal to -10. So, we have

\frac{2}{3}x≤-10

In order to cancel out the \frac{2}{3} on the left and isolate x, we multiply both sides by \frac{3}{2} (since \frac{3}{2}·\frac{2}{3}=1). Thus, we have

x≤-10·\frac{3}{2}=-15

Therefore, x≤-15

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Please help me on this
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For this case we have to define root properties:

\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a

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a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

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3 years ago
Question 6 (Essay Worth 2 points)<br> Find all polar coordinates of point P = (2, 14°).
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(2,14°+360n) and (-2,14°+(2n+1)180°)

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You start out with (2, 14°)

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(r,0)=(-r,0+2(n=1)π), where n is any integer.

The polar coordinates point : p=(r,0) = (2,14°)

For the positive value of r,  the polar coordinate can be written as

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For the negative value of r ,  the polar coordinate can be written as

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All the polar coordinates of point P are(2,14°+360n) and (-2,14°+(2n+1)180°).

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