<u><em>28.1 feet</em></u>
<u><em></em></u>
<em><u>explaination</u></em>
<u><em>\cos U = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{9.6}{x}</em></u>
<u><em>cosU= </em></u>
<u><em>hypotenuse</em></u>
<u><em>adjacent</em></u>
<u><em> </em></u>
<u><em> = </em></u>
<u><em>x</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> </em></u>
<u><em>\cos 70=\frac{9.6}{x}</em></u>
<u><em>cos70= </em></u>
<u><em>x</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> </em></u>
<u><em>x\cos 70=9.6</em></u>
<u><em>xcos70=9.6</em></u>
<u><em>Cross multiply.</em></u>
<u><em>\frac{x\cos 70}{\cos 70}=\frac{9.6}{\cos 70}</em></u>
<u><em>cos70</em></u>
<u><em>xcos70</em></u>
<u><em> </em></u>
<u><em> = </em></u>
<u><em>cos70</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> </em></u>
<u><em>Divide each side by cos 70.</em></u>
<u><em>x=\frac{9.6}{\cos 70}=28.0685\approx 28.1\text{ feet}</em></u>
<u><em>x= </em></u>
<u><em>cos70</em></u>
<u><em>9.6</em></u>
<u><em> </em></u>
<u><em> =28.0685≈28.1 feet</em></u>
<u><em>Type into calculator and roundto the nearest tenth of a foot.</em></u>
<h2>
<u>Sol</u><u>ution</u><u>:</u></h2>
Equation: x² + 10x + 21
<u>Step</u><u> </u><u>1</u><u>:</u> Find two numbers that can add up to 10 and be multiplied to 21. We have: 7 & 3, in the sense that 7+3=10, and 7×3=21. Replacing 10 with 7+3, the equation is now → x² + 7x + 3x + 21
<u>Step</u><u> </u><u>2</u><u>:</u> Get the new equation bracketed → (x² + 7x) (+3x + 21)
<u>Step</u><u> </u><u>3</u><u>:</u> Use 'x' in the equation. For the first part, we have 'x'. x² = x × x so, bring out one x out side the bracket, divide 7x by = 7 → x (x +7). Do the same for the second part by dividing 21 by 3 = 7, and then bringing out 3 from the bracket → 3 (x + 7).
Bringing everything together, we have: x(x+7) +3(x+7) → (x+3) (x+7)
<h3>
<u>Final</u><u> </u><u>ans</u><u>wer</u><u>:</u></h3>
(x+3) (x+7)
<h3 />
You can do like this
This is my answer 1 to 10
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Answer:
Yes
Step-by-step explanation: If the inside of the ange is obtuse than it is acute