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3 years ago

PLEASE HELP PLEASE HELP

Mathematics

1 answer:

Arlecino [84]3 years ago

6 0

The values in the ordered pairs of a function are swapped to define its inverse. The appropriate choice is the one that looks like ...

... (-8, 5)

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Fill in the next entry in the pattern 81, 27, 9, 3,

Dominik [7]

The answer to your problem is 1

6 0

3 years ago

Read 2 more answers

Please help!!! ASAP With all these questions

andrey2020 [161]

#1. 4:7 8:14 12:21
#2. 5:7 10:14 15:21
#3. 9:7 18:14 27:21
#4. 11:2 22:4 33:6
#5. 7:21 14:42 21:63
#6. 7:5 14:10 21:15
#7. Equals
#8. Equals
#9. Equals
#10 not equal
#11 not equal
# 12. Equals
#13. y=20
#14. y=14
#15. y=15
#16. y=40
#17. y=40
#18. y=36

7 0

3 years ago

Describe and correct the error(s) made in each of the problems below.

ladessa [460]

Answer:

$\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}$

$\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}$

Step-by-step explanation:

Errors in Algebraic Operations

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

$1-x / (5-x)(-x)=x-1 / x(x-5)$

Let's arrange into format:

$\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}$

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

$\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}$

Now for the second expression

$5/s+2/5=2/s$

Let's arrange into format

$\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}$

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

$\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}$

6 0

2 years ago

A membership at a yoga studio costs $35 per month. Write an equation for the cost of the membership, c, that you pay if you keep

Usimov [2.4K]

Since there is no base down payment or anything the equation i think would just be 35m = c
If there was say a one time payment of $20 and then the monthly payments it would look like 20+35m=C
I hope this helps :)

6 0

3 years ago

Law of Sines or Law of Cosines....Help!!

iren2701 [21]

Answer:

Law of cosines to find missing measures

c^2= a^2+ b^2 - 2ab*cos(C)

Used because it is a SAS triangle

Step-by-step explanation:

This is known as a side, angle, side, or SAS triangle. We can find the missing measures by using the Law of cosines

c^2= a^2+b^2-2ab*cos(C)

7 0

2 years ago