How many 2/3 are in 8/9

Mathematics

2 answers:

Mila [183]3 years ago

6 0

Answer:

3/4 or 0.75 decimal

Step-by-step explanation:

Simplify the following:

(2/3)/(8/9)

Hint: | Write (2/3)/(8/9) as a single fraction.

Multiply the numerator by the reciprocal of the denominator, (2/3)/(8/9) = 2/3×9/8:

(2×9)/(3×8)

Hint: | In (2×9)/(3×8), divide 9 in the numerator by 3 in the denominator.

9/3 = (3×3)/3 = 3:

(2×3)/8

Hint: | In (2×3)/8, divide 8 in the denominator by 2 in the numerator.

2/8 = 2/(2×4) = 1/4:

Answer: 3/4

zlopas [31]3 years ago

3 0

Answer: I'm pretty sure it's 3/4

Hope this helps! :3

Step-by-step explanation:

Idk -w- sorry

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Kipish [7]

Answer:

im not able to do that question it is confusing

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5 0

3 years ago

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

DENIUS [597]

Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

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