Answer:
The overview of the situation is discussed in the following part.
Explanation:
It's indeed real that perhaps IT technology will have a strategic edge and improved market efficiency. IT technology can improve the protection, accessibility, and efficiency of any enterprise.
Numerous massive, small as well as medium-sized companies or beginning are currently preparing their growth plans by sustaining a stable IT infrastructure throughout the place that will ensure and increase their profitability.
<u>Those same years, the accompanying IT infrastructure is being used to connect the market strategy</u>:
- Broadband and Wireless Connectivity,
- Security and Risk Management,
- IT Structure Strategy,
- Performance Strategy, etc.
Answer:
The solution code is written in Python 3.
- def convertDate(date_string):
-
- date_list = date_string.split("/")
-
- for i in range(0, len(date_list)):
- date_list[i] = int(date_list[i])
-
- return date_list
-
-
- print(convertDate('06/11/1930'))
Explanation:
Firstly, create a function convertDate() with one parameter, <em>date_string</em>. (Line 1).
Next, use the Python string <em>split()</em> method to split the date string into a list of date components (month, day & year) and assign it to variable <em>date_list</em>. (Line 3) In this case, we use "/" as the separator.
However, all the separated date components in the <em>date_list</em> are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python<em> int() </em>function. (Line 5 - 6)
At last return the final date_list as the output (Line 8)
We can test our function as in Line 11. We shall see the output is as follow:
[6, 11, 1930]
Answer:
see explaination
Explanation:
function [] =
inverse(A,B)
da = det(A);
disp("The det of A is");
disp(da);
inva = inv(A);
disp("The inverse of A is");
disp(inva);
x = inva*B;
disp("The value of X is");
disp(x);
rk = rank(A);
disp("The rank of X is");
disp(rk);
Di = eig(A);
disp("The eigen values of A is");
disp(Di);
[V,Di] = eig(A);
disp("The eigen vectors of A are (Each column represents one column vector)");
disp(V);
end
A = [1,2;4,5];
B = [1,2;4,5];
inverse(A,B);
%ab = [num2str(t)," ",num2str(dx)," ",num2str(dy)];
%disp(ab);
Answer:
D. 4x as much
Explanation:
The answer is pretty simple. The question is asking about 10m/s and 20m/s right? Take a look at the energy at each point on the graph. At 10m/s the kinetic energy is 100 on the graph. At 20m/s the kinetic energy is 400. You'll notice that 100 x 4 is 400 - That's the answer.
You can also prove this mathematically. The formula for kinetic energy is
The question says: constant mass so we can ignore that for now.
(1/2) * 10^2 is (1/2) * 100 = 50
for the 20m/s ball it would be
(1/2) * 20^2 = 400 * 1/2 = 200
Once again, you see that it is 4x
