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3 years ago

How are computers 35 years ago and how are they presently and how are they going to be in the next 35 years

Computers and Technology

1 answer:

antoniya [11.8K]3 years ago

5 0

Answer:

Jason = 20yrs.old

Mandy = 15yrs.old

Explanation:

Let

J = Jason's age

M = Mandy's age

J+M=35 ..... eq. 1

J−10=2(M−10) ..... eq. 2

From eq. 1

J=35−M

Substitute this in eq. 2.

(35−M)−10=2(M−10)

35−10−M=2M−20

35−10+20=2M+M

45=3M

453=3M3

15=M

J=35−M

J=35−15

J=20

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3 years ago

Read 2 more answers

2.36 LAB: Warm up: Variables, input, and casting (1) Prompt the user to input an integer, a double, a character, and a string, s

Westkost [7]

Answer:

The entire program is:

#include <iostream>

using namespace std;

int main() {

int userInt;

double userDouble;

char userChar;

string userString;

cout<<"Enter integer:"<<endl;

cin>>userInt;

cout<<"Enter double:"<<endl;

cin>>userDouble;

cout<<"Enter character:"<<endl;

cin>>userChar;

cout<<"Enter string:"<<endl;

cin>>userString;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl;

cout<<endl;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl;

cout<<endl;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl<<userDouble<<" cast to an integer is "<<(int)userDouble;

return 0; }

The program in C language:

#include <stdio.h>

int main() {

int userInt;

double userDouble;

char userChar;

char userString[50];

printf("Enter integer: \n");

scanf("%d", &userInt);

printf("Enter double: \n");

scanf("%lf", &userDouble);

printf("Enter character: \n");

scanf(" %c", &userChar);

printf("Enter string: \n");

scanf("%s", userString);

printf("%d %lf %c %s\n", userInt, userDouble, userChar, userString);

printf("\n");

printf("%d %lf %c %s\n%s %c %lf %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt);

printf("\n");

printf("%d %lf %c %s\n%s %c %lf %d\n%lf cast to an integer is %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt, userDouble, (int)userDouble); }

Explanation:

Lets do the program step by step:

1) Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output those four values on a single line separated by a space:

Solution:

The program is:

#include <iostream> //to use input output functions

using namespace std; //to identify objects cin cout

int main() { //start of main method

//declare an integer, a double, a character and a string variable

int userInt; //int type variable to store integer

double userDouble; //double type variable to store double precision floating point number

char userChar; //char type variable to store character

string userString; //string type variable to store a string

cout<<"Enter integer:"<<endl; //prompts user to enter an integer

cin>>userInt; //reads the input integer and store it to userInt variable

cout<<"Enter double:"<<endl; //prompts user to enter a double type value

cin>>userDouble; //reads the input double value and store it to userDouble variable

cout<<"Enter character:"<<endl; //prompts user to enter a character

cin>>userChar; //reads the input character and store it to userChar variable

cout<<"Enter string:"<<endl; //prompts user to enter a string

cin>>userString; //reads the input string and store it to userString variable

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl; //output the values on a single line separated by space

So the output of the entire program is:

Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy

(2) Extend to also output in reverse.

Now the above code remains the same but add this output (cout) statement at the end:

cout<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt;

Now the output with the same values given as input is:

Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy

99 3.77 z Howdy Howdy z 3.77 99

(3) Extend to cast the double to an integer, and output that integer.

The rest of the code remains the same but add the following output (cout) statement in the end:

cout<<userDouble<<" cast to an integer is "<<(int)userDouble;

Now the output with the same values given as input is:

Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy Howdy z 3.77 99 3.77 cast to an integer is 3

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3 years ago

Write the function definition for a function called list_total that accepts a list of integers

uranmaximum [27]

Answer:

def list_total(numbers):

sum_of_numbers = 0

for number in numbers:

sum_of_numbers += number

return sum_of_numbers

Explanation:

So, to define a function, the syntax is simply:

def functionName(arguments here):

# code

So to define a function called "list_total" which accepts a list of integers, you write:

def list_total(numbers):
# code

any the "numbers" is a parameter, and it's just like any variable, so you can name it anything besides keywords. I just named it "numbers" since it makes sense in this context, you could also write "integers" instead and it would be just as valid, and may be a bit more specific in this case.

Anyways from here, the initial sum should be equal to 0, and from there we add each number in the list to that initial sum. This can be done by initializing a variable to the value "0" and then traversing the list using a for loop. This can be done as such:

def list_total(numbers):

sum_of_numbers = 0

for number in numbers:

# code

So for each element or integer in the list "numbers" the for lop will run, and the variable "number" will contain the value of the current element it's on.

So we can add the "number" to the sum_of_numbers as such:

sum_of_numbers = sum_of_numbers + number

but there is a shorter way to do this, and it's represented as:

sum_of_numbers += sum_of_numbers

which will do the same exact thing. In fact this works for any mathematical operation for example:

a *= 3

is the same thing as

a = a * 3

and

a /= 3

is the same thing as

a = a / 3

It's the same thing, but it's a much shorter and more readable notation.

Anyways, this code will go in the for loop to almost finish the code

def list_total(numbers):

sum_of_numbers = 0

for number in numbers:

sum_of_numbers += number

The last thing is to return this value, and this is simply done by using the syntax:

"return {value here}"

and since the sum_of_numbers has the value, we write

"return sum_of_numbers"

at the end of the function, which is very very important, because when you use the return keyword, you end the function, and return whatever value is next to the return to the function call

So to finish the code we just add this last piece to get:

def list_total(numbers):

sum_of_numbers = 0

for number in numbers:

sum_of_numbers += number

return sum_of_numbers

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1 year ago

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jeka94

CTRL+HOME then delete, backspace, end.

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3 years ago

20 points

adoni [48]

Yes it's important. It's like taking jotting down the ideas you have for a project, you don't want to forget anything, and these things help you keep track of what you want to do.

Answer would be false.

4 0

3 years ago