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4 years ago

What is the width of the loop along the horizontal axis and determine the height.

Mathematics

1 answer:

miv72 [106K]4 years ago

7 0

Horizontal width=100
height= 25+2*65=155

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What is the answer in a whole number or decimal

GenaCL600 [577]

Answer:

i = 8

Step-by-step explanation:

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3 years ago

What is the solution set of the given system?

AVprozaik [17]

What is the system? (Is there supposed to be an image?)

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3 years ago

Compare the area of a rectangle whose sides are 3 and 1/9 inches by 4 and 2/3 inches to a rectangle whose sides are 3 and 2/3 in

attashe74 [19]

Area of a rectangle 1=L*W
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Area=28/9*14/3=14.518 inches^2

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area=11/3*21/5
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Area of a rectangle 2 is more by 0.88 inche^2

4 0

4 years ago

Read 2 more answers

Evaluate each of the following. (a) P(11,5) (b) C(11,5) (a) P(11,5) = (Simplify your answer.) (b) C(11,5) = (Simplify your answe

Hunter-Best [27]

<h2>Answer:</h2>

(a) P(11,5)= 55440

(b) C(11,5)=462

<h2>Step-by-step explanation:</h2>

We know that the permutation is the number of ways of arranging r items out of a total of n items and is given by:

$P(n,r)=\dfrac{n!}{(n-r)!}$

and the combination is the number of ways of choosing r items out of a total of n items and is given by:

$C(n,r)=\dfrac{n!}{r!\times (n-r)!}$

(a)

P(11,5)

$P(11,5)=\dfrac{11!}{(11-5)!}\\\\P(11,5)=\dfrac{11!}{6!}\\\\P(11,5)=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{6!}\\\\P(11,5)=11\times 10\times 9\times 8\times 7\\\\P(11,5)=55440$

(b)

C(11,5)

$C(11,5)=\dfrac{11!}{5!\times (11-5)!}\\\\C(11,5)=\dfrac{11!}{5!\times 6!}\\\\C(11,5)=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{5\times 4\times 3\times 2\times 1\times 6!}\\\\C(11,5)=462$

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3 years ago

1/3(x+3) - 2/x+3, where x is not equal to negative 3

myrzilka [38]

If $x\neq 3$ , then

$\frac{1}{3(x+3)} - \frac{2}{x+3} = \frac{1\cdot 1-2\cdot 3}{3(x+3)} = \frac{-5}{3(x+3)} =- \frac{5}{3(x+3)}$ .

5 0

3 years ago