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Montano1993 [528]
3 years ago
11

Give an example of two numbers that are both 6 digit numbers, but the greater number is determined by the hundreds place

Mathematics
2 answers:
lukranit [14]3 years ago
6 0
234,560
232,560
Is what an answer could be for this.
Arte-miy333 [17]3 years ago
4 0
302,567>248,432 since 500 is bigger than 400 so 302,567 is bigger
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Step-by-step explanation:

<u>Step 1:  Combine like terms</u>

7 + -7x + -8 - 9x + 5

7 - 7x - 8 - 9x + 5

4 - 16x

<u>Step 2:  Solve for x</u>

4 - 16x - 4 = 0 - 4

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ABCD is a rectangle. The measure of angle BCE is 4x-23 and the angle measure of angle DCE is 5+5x. Find the measure of angle BEC
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<h2>Explanation:</h2><h2></h2>

The diagram for this problem is shown below. Point E is the intersection of the two diagonals and we know that:

\angle BCE=\beta \\ \\ \angle DCE=\theta

Every internal angle of any rectangle measures 90 degrees, so:

\beta +\alpha=90 \\ \\ (4x-23)+(5+5x)=90 \\ \\ \\ Isolating \ x: \\ \\ (4x+5x)+(5-23)=90 \\ \\ 9x-18=90 \\ \\ 9x=108 \\ \\ x=\frac{108}{9}=12

So:

\beta=4x-23=4(12)-23=25^{\circ}

So the measure of angle BEC can be found as follows:

We know that triangle ΔCEB is an isosceles triangle because the diagonals of any rectangle measure the same. So

\angle EBC=\beta

The sum of internal angles of any triangle add up to 180 degrees, so:

\beta + \beta+\angle BEC=180^{\circ} \\ \\ 2\beta+\angle BEC=180^{\circ} \\ \\ \angle BEC=180^{\circ}-2\beta \\ \\ \angle BEC=180^{\circ}-2(25^{\circ}) \\ \\ \angle BEC=180^{\circ}-50^{\circ} \\ \\ \boxed{\angle BEC=130^{\circ}}}

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