Answer:
Part 1) ![x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D%28x-1-%5Csqrt%7B3%7D%29%28x-1%2B%5Csqrt%7B3%7D%29)
Part 2) ![x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D%28x-3-%5Csqrt%7B5%7D%29%28x-3%2B%5Csqrt%7B5%7D%29)
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
![ax^{2} +bx+c=0](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%2Bbx%2Bc%3D0)
is equal to
![x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
Part 1)
in this problem we have
![x^{2} -2x-2=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D0)
so
![a=1\\b=-2\\c=-2](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-2%5C%5Cc%3D-2)
substitute in the formula
![x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-2%29%28%2B%2F-%29%5Csqrt%7B-2%5E%7B2%7D-4%281%29%28-2%29%7D%7D%20%7B2%281%29%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B2%28%2B%2F-%29%5Csqrt%7B12%7D%7D%20%7B2%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B2%28%2B%2F-%292%5Csqrt%7B3%7D%7D%20%7B2%7D%5C%5C%5C%5Cx_1%3D%5Cfrac%7B2%28%2B%292%5Csqrt%7B3%7D%7D%20%7B2%7D%3D1%2B%5Csqrt%7B3%7D%5C%5C%5C%5Cx_2%3D%5Cfrac%7B2%28-%292%5Csqrt%7B3%7D%7D%20%7B2%7D%3D1-%5Csqrt%7B3%7D)
therefore
![x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D%28x-%281%2B%5Csqrt%7B3%7D%29%29%28x-%281-%5Csqrt%7B3%7D%29%29)
![x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D%28x-1-%5Csqrt%7B3%7D%29%28x-1%2B%5Csqrt%7B3%7D%29)
Part 2)
in this problem we have
![x^{2} -6x+4=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D0)
so
![a=1\\b=-6\\c=4](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-6%5C%5Cc%3D4)
substitute in the formula
![x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-6%29%28%2B%2F-%29%5Csqrt%7B-6%5E%7B2%7D-4%281%29%284%29%7D%7D%20%7B2%281%29%7D)
![x=\frac{6(+/-)\sqrt{20}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B6%28%2B%2F-%29%5Csqrt%7B20%7D%7D%20%7B2%7D)
![x=\frac{6(+/-)2\sqrt{5}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B6%28%2B%2F-%292%5Csqrt%7B5%7D%7D%20%7B2%7D)
![x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}](https://tex.z-dn.net/?f=x_1%3D%5Cfrac%7B6%28%2B%292%5Csqrt%7B5%7D%7D%7B2%7D%3D3%2B%5Csqrt%7B5%7D)
![x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}](https://tex.z-dn.net/?f=x_2%3D%5Cfrac%7B6%28-%292%5Csqrt%7B5%7D%7D%7B2%7D%3D3-%5Csqrt%7B5%7D)
therefore
![x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D%28x-%283%2B%5Csqrt%7B5%7D%29%29%28x-%283-%5Csqrt%7B5%7D%29%29)
![x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D%28x-3-%5Csqrt%7B5%7D%29%28x-3%2B%5Csqrt%7B5%7D%29)
Answer:
60
Step-by-step explanation:
17-20=3. 60times3 equals 180. So 60
Answer:
D
Step-by-step explanation:
The "Let something else figure this out answer" should be attempted with a graph. Start with the graph of f(x) = (x)^(1/3)
When you have that, you know that the graph has been shift right 1 unit which means that you are after g(x) = (x - 1)^(1/3) which means that only B or D can be correct, but which is it. The difference between the two is the minus sign. Is it g(x) = (x - 1)^(1/3) or is it g(x) = -(x - 1)^(1/3)? It turns out that it is g(x) = - (x - 1)^(1/3) because that creates a reflection across the x axis.
The graph is a bit confusing because I've chosen to put all three graphs on the same axis, which is not the clearest thing to do. But if you study it carefully you'll see which is the answer.
Red: f(x) = (x)^(1/3)
Blue: g(x) = (x - 1)^(1/3)
green:g(x) = -(x - 1)^(1/3) [ Closest to your given graph]
Answer: Green (D)
Hiya! :D
My name is Violet, and I will be helping you on your question!
![\sf{7j \: + 3 \: - 4j \: + \: 9}](https://tex.z-dn.net/?f=%5Csf%7B7j%20%5C%3A%20%2B%203%20%5C%3A%20-%204j%20%5C%3A%20%2B%20%5C%3A%209%7D)
![\sf{Group \: like \: terms:}](https://tex.z-dn.net/?f=%5Csf%7BGroup%20%5C%3A%20like%20%5C%3A%20terms%3A%7D)
![\sf{= 7j \: - 4j \: + \: 3 \: + \: 9}](https://tex.z-dn.net/?f=%5Csf%7B%3D%207j%20%5C%3A%20-%204j%20%5C%3A%20%2B%20%5C%3A%203%20%5C%3A%20%2B%20%5C%3A%209%7D)
![\sf{Add \: the \: numbers:}~ 3 \: + \: 9 \: = 12}](https://tex.z-dn.net/?f=%5Csf%7BAdd%20%5C%3A%20the%20%5C%3A%20numbers%3A%7D~%203%20%5C%3A%20%2B%20%5C%3A%209%20%5C%3A%20%3D%2012%7D)
![\sf{= 7j \: - \: 4j \: + \: 12}](https://tex.z-dn.net/?f=%5Csf%7B%3D%207j%20%5C%3A%20-%20%5C%3A%204j%20%5C%3A%20%2B%20%5C%3A%2012%7D)
![\sf{Add \: similar \: elements:}~ 7j \: - 4j \: = \: 3j}](https://tex.z-dn.net/?f=%5Csf%7BAdd%20%5C%3A%20similar%20%5C%3A%20elements%3A%7D~%207j%20%5C%3A%20-%204j%20%5C%3A%20%3D%20%5C%3A%203j%7D)
![\sf{= 3j \: + \: 12}](https://tex.z-dn.net/?f=%5Csf%7B%3D%203j%20%5C%3A%20%2B%20%5C%3A%2012%7D)
Hope It Helps ! ^-^
#LearnWithBrainly
![\underline{Answer :}](https://tex.z-dn.net/?f=%5Cunderline%7BAnswer%20%3A%7D)
![\huge \pmb {\frak{Violet}}](https://tex.z-dn.net/?f=%5Chuge%20%5Cpmb%20%7B%5Cfrak%7BViolet%7D%7D)
Answer:
2y=299
Step-by-step explanation:
:)