The vertices of a triangle are P[4.1). Q(2.-8), and R(-8.1). What are the vertices of the image reflected across the y-axis?
1 answer:
Given:
The vertices of a triangle are P(4,1), Q(2,-8), and R(-8,1).
To find:
The vertices of the image reflected across the y-axis.
Solution:
The vertices of a triangle are P(4,1), Q(2,-8), and R(-8,1). It is reflected across the y-axis.
If a figure is reflected across the y-axis, then
Using this rule, we get
So, the vertices of the image are .
Therefore, the correct option is B.
Note: Options are not in proper form.
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Given:
To prove:
Proof:
In ,
because Given
because Given
because Reflexive property.
Corresponding sides of both triangles are congruent. So,
because SSS
Therefore, the required missing values are: Given, , Reflexive property ,
, SSS respectively.
Answer:
the parabola can be written as:
f(x) = y = a*x^2 + b*x + c
first step.
find the vertex at:
x = -b/2a
the vertex will be the point (-b/2a, f(-b/2a))
now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.
The next step is to see if we have real roots by using the Bhaskara's equation:
Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.
If you do not have any real roots, you can feed into the parabola some different values of x around the vertex
for example at:
x = (-b/2a) + 1 and x = (-b/2a) - 1
those two values should give the same value of y, and now you can connect the vertex with those two points.
If you want a more exact drawing, you can add more points (like x = (-b/2a) + 3 and x = (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.