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Ahat [919]
3 years ago
5

A club with 16 members is to choose three officers president vice president and secretary treasurer if each office is to be held

by one person and no person can hold more than one office in how many ways can those offices be filled?
Mathematics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

The offices can be filled in 3,360 ways

Step-by-step explanation:

In this question, we are faced with a selection problem.

There are three offices and 3 officers to be selected.

For the first position, we are to select 1 out of 16. Now, for the second position, we are left with 15 members from which we are to select one. This is because the first selection has been picked and cannot partake in the subsequent selections.

Likewise for the third position, we are selecting 1 out of 14

The number of ways this can be done is thus; 16C1 × 15C1 × 14C1 = 16 × 15 × 14 = 3,360 ways

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The required probability for three numbers rolled on the dice are the sides of a triangle is 31/36.

<h3>What is probability?</h3>

The area of mathematics known as probability studies potential outcomes of events as well as their relative probabilities and distributions. It is based on the likelihood that something will occur. The justification for probability serves as the main foundation for theoretical probability.

Here,

When three dice are rolled, there are 63=216 possible outcomes, or triplets (x, y, z).

Once more, in a triangle, any two sides added together are larger than the third side, or (x+y)>z.

As a result, 186 outcomes or triplets are possible and satisfy this property.

Hence, the required probability is 186/216=31/36.

The required probability is 31/36 for three dice rolls to produce triangle sides.

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1 year ago
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