Answer:
hi there ☺️
Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 345
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 345
3X + 3 = 345
3X + 3 - 3 = 345 - 3
3X = 342
3X/3 = 342/3
X = 114
Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.
114 + 115 + 116 = 345
We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.
Step-by-step explanation:
pls rate me the brainiest
Usually, quadratic equations equal 0, and to find the solution you need to make x equal the value that, when added or subtracted to the rest of its bracket, makes 0. This means that your answer is (x + 5)(x - 2) = 0, because 5 - 5 = 0 and 2 - 2 = 0. I hope this helps! Let me know if you would like me to explain further :)
Answer:
I think that -0.0000002 is the least, but I don't know the rest. I hope you can find the rest though. Happy Holidays!
Step-by-step explanation:
1 more than 9 is 10.
That is because 10-9 = 1.
My best Guess is
1.282 for upper . , -1.282 for lower.
Hope this Helps
-Dante
