<em>Greetings from Brasil</em>
Let us call the distance AB of Y (in the problem nothing is said about this dimension, so lets call of Y).
From the attached drawing we can conclude that:
AB + BC = AC
where
AB = Y
BC = 2X + 4
AC = 24
then
AB + BC = AC
Y + (2X + 4) = 24
<h2>X = (20 - Y)/2</h2>
<em>In my view this question is incomplete</em>
Answer:
18.3
Step-by-step explanation:
384.3 divided by 21
If it moves 4.5 times a year and each time it moves 10 meters, one one year it moves 45 meters. Now we want 11 years, so that's 45 times 11 which would give you 495 meters in 11 years
Answer:
Distance of ladder from base = 4.22 feet (Approx.)
Step-by-step explanation:
Given:
Length of ladder = 10 feet
Angle with ground = 65°
Find:
Distance of ladder from base
Computation:
Length of ladder (hypotenuse) = 10 feet
Distance of ladder from base (Base)
Using trigonometry function
Cosθ = Base / Hypotenuse
Cosθ = Distance of ladder from base / Length of ladder
Cos65 = Distance of ladder from base / 10
0.4226 = Distance of ladder from base / 10
Distance of ladder from base = 0.4226 x 10
Distance of ladder from base = 4.226
Distance of ladder from base = 4.22 feet (Approx.)
