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Zolol [24]
2 years ago
9

Someone help me pls i need to pass summer school

Mathematics
2 answers:
scoray [572]2 years ago
5 0

Answer:

A

Step-by-step explanation:

The be the inverse function the domain {4,5,6,7} becomes the range and the range {14,12,10,8} becomes the domain

14 → 4

12 →5

10 →6

8 →7

aleksandr82 [10.1K]2 years ago
3 0
16 to the 0 power 16 to the 0 power 16 to the 0 power 16 to the 0 power 16 to the 0 power
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The lines graphed below are perpendicular. The slope of the redline is -2. What is the slope of the green line
attashe74 [19]

Answer:

It would be undefined if the line is vertical.

Step-by-step explanation:

6 0
3 years ago
Unitary method
tangare [24]

Answer:

60 kilometers per hour.

420 kilometers will be covered

Step-by-step explanation:

speed = distance ÷ time.

so 60kmh = 240km divided by 4 Hours

60km = 1 Hour of distance

240km = 4 Hours of distance

Therefore 60 x 3 hour is 180km added to 240 is 420km. So in 7 hours traveling 60 kilometers per hour the will cover 420kms.

4 0
2 years ago
Find the area 2 m 4 m 10 m
mina [271]

Answer:

30.285 m²

Step-by-step explanation:

C = 2πr

2 · π · 2

≈ 12.57

12.57 ÷ 2 = 6.285

10 - 2 = 8

8 · 4 ÷ 2

32 ÷ 2

16

2 · 4 = 8

6.285 + 8 + 16

30.285

6 0
3 years ago
Determine the current through each of the LEDs in the circuits below. Which LED will be
Anika [276]

a. I = 6. 1 × 10^-4 A

b. I = 2. 6 × 10^-3 A

c. I = 0. 04 A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

I = \frac{12}{19700}

I = 6. 1 × 10^-4 A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

I = \frac{12}{4700}

I = 2. 6 × 10^-3 A

C.  V=  12V

1/R = \frac{1}{750} + \frac{1}{1200} + \frac{1}{950 } = 3. 22 × 10^-3

R = \frac{1}{3. 22 * 10 ^-3} = 310. 56 Ω

I = \frac{12}{310. 56}

I = 0. 04 A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

8 0
2 years ago
Use the discriminant to determine the number of real solutions to the quadratic equation.
gulaghasi [49]

Answer:

There are two real and different roots

Step-by-step explanation:

The discriminant is given by b²-4ac

(-12)²-4(70×1)

144-280

136

Now 136>0

5 0
2 years ago
Read 2 more answers
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