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shtirl [24]
3 years ago
11

How do you round to the nearest hundredth?

Mathematics
1 answer:
Sati [7]3 years ago
3 0
You stop at 2 decimal points. If the 3rd decimal is bigger than 5, add 1 to the 2nd and if it's less than 5, keep it as it is.
For example:
2.663 --> 2.66
6.788 --> 6.79
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adult tickets to a movie cost $12 while children tickets cost $5. if a total of 500 tickets were sold and if $3550 was collected
svp [43]
The answer to the question

5 0
3 years ago
Can someone explain how to solve this and the solution? Please and thank you :)
Verizon [17]
25 > 2x + 8 - 66

first simplify all numbers

25 > 2x + (8  - 66)
25 > 2x - 58

Then add 58 to both sides

25 (+58) > 2x - 58 (+58)
83 > 2x

Finally divide 2 from both sides to isolate the x

83/2 > 2x/2

41.5 > x

hope this helps
3 0
2 years ago
Find the explicit formula for the given sequence.<br> 1,5, 25, 125, ....
Lyrx [107]

Answer:

you keep multiplying by five

Step-by-step explanation:

So 1 x 5 is five, 5 x 5 is 25, 25 x 5 is 125, so on and so forth.

8 0
3 years ago
Please help with problems 6 and 7.
monitta
6 is A and seven is B
7 0
3 years ago
7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and
Juliette [100K]

Answer:

A) JK and AB =

[tex] \boxed{( \theta) = \f{12}{( \theta)} } So, =》 \dfrac{10}{5} = \dfrac{1}{ \( \theta) } =》 \( \theta) = \dfrac{5}{2}[/tex]

B) AABC

[tex] \boxed{( \theta) = {1}{( \theta)} } So, 23}{-18=\\Ans } \boxed

C) AABM:

[tex] e \fbox{: } The value of k for which \sin(jm) = \cos(x) is \dfrac{\p}{2} ans[/tex]

----------

3 0
3 years ago
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