All categories

3 years ago

Which distances is least to greatest 1/8, 3/16 and 3/4 or 3/4, 1/8 and 3/16

Mathematics

2 answers:

antoniya [11.8K]3 years ago

6 0

The first one, 1/8, 3/16, and 3/4, are from least to greatest.

Marina CMI [18]3 years ago

4 0

The first choice given is correct, because 3/4 is closest to 1, and 1/8 is farthest from 1

You might be interested in

Brainliest to whoever gets it right first

Inga [223]

I just guessed and it is 108

3 0

3 years ago

HELP ME PLEASE

Mashutka [201]

Answer:

$9 + \frac{n}{3} - 6 = 7$

Step-by-step explanation:

Given

$9 + \frac{n}{3} - 6$

Required

Evaluate when n = 12

Substitute 12 for n in $9 + \frac{n}{3} - 6$

$9 + \frac{n}{3} - 6 = 9 + \frac{12}{3} - 6$

Simplify the fraction

$9 + \frac{n}{3} - 6 = 9 + 4 - 6$

$9 + \frac{n}{3} - 6 = 7$

4 0

3 years ago

Find an equation of the ellipse that has center (-2,0), a minor axis of length 2, and a vertex at (8,0)

Viefleur [7K]

Answer:

Step-by-step explanation:

(-2,0) and (8,0) are horizontally aligned, so the ellipse is horizontal.

6 0

3 years ago

Find the remainder when 1 + 2 + 2^2 + 2^3 + ... + 2^100 is divided by 7.<br><br> Thanks in advance!

Firlakuza [10]

Answer:

Step-by-step explanation:

This is a geometric series so the sum is:

a1 * r^n - 1 / (r - 1)

= 1 * (2^101 -1) / (2-1)

= 2^101 - 1.

Find the remainder when 2^101 is divided by 7:

Note that 101 = 14*7 + 3 so

2^101 = 2^(7*14 + 3) = 2^3 * (2^14)^7 = 8 * (2^14)^7.

By Fermat's Little Theorem (2^14) ^ 7 = 2^14 mod 7 = 4^7 mod 7.

So 2^101 mod 7 = (8 * 4^7) mod 7

= (8 * 4) mod 7

= 32 mod 7

= 4 = the remainder when 2^101 is divided by 7.

So the remainder when 2^101- 1 is divided by 7 is 4 - 1 = 3..

4 0

3 years ago

$4000 is invested in a mutual fund that pays annual interest compounded quarterly for 15 years. What annual interest is needed t

Neporo4naja [7]

Answer:

The interest needed to reach that value of $6000 is 2.75%

Step-by-step explanation:

Given as :

The principal that invested in mutual fund = p = $4000

The time period = t = 15 years

The Amount after 15 years = A = $6000

Let The interest needed to reach that value = r%

Now, According to question

<u>From Compound Interest method</u>

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, $6000 = $4000 × $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $\dfrac{6000}{4000}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

Or, $\frac{3}{2}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, 1.5 = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $1.5^{\frac{1}{15}}$ = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 - 1 = $\dfrac{r}{100}$

or, 0.0275 = $\dfrac{r}{100}$

∴ r = 0.0275 × 100

I.e r = 2.75

So, The interest needed to reach that value = r = 2.75%

Hence,The interest needed to reach that value of $6000 is 2.75% Answer

3 0

3 years ago