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Inessa05 [86]
2 years ago
11

The population of DeSoto rose an

Mathematics
1 answer:
Vanyuwa [196]2 years ago
4 0

Answer:

Please check explanations

Step-by-step explanation:

Here, we want to make an interpretation

From the question, we have that initially when the count was started, there were 5,428 people; this means that the initial value of the data is 5,428

For the rate of change, we have that there is an average increase of 142 people for each of 5 years;

That means per 5 years, there is an increase of 142 people and this is what represents the rate of change

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Madeline is saving up to buy a new jacket. She already has $65 and can save an
Anestetic [448]

Answer:

$90

Step-by-step explanation:

7 0
2 years ago
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Write the equation of a vertical line that passes through the point (–4, 4).
FinnZ [79.3K]
The question asks for a vertical line, and if it is vertical, it cannot be y = ... because that is horizontal. We also know it passes through the x-coordinate of -4, so the answer is x = -4. 
4 0
3 years ago
Determine if the two triangles are congruent.If they are state how you know
Finger [1]

Answer:

1. yes, both triangles sides are congruent

2. yes, they have congruent sides and they have a congruent angle

3. yes, congruent sides and angle

4. yes, 2 congruent angles

5. no, only one congruent angle not enough proof

6. yes, 2 congruent angles

7. no, only one congruent angle not enough proof

8. no, only one congruent side

6 0
2 years ago
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Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth
taurus [48]

Answer:

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\

It is a homogeneous solution:

y_h(t)=c_1e^{-2i t}+c_2e^{2i t}

Now, we finding a particular solution.

y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\

we get

y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

7 0
3 years ago
Find the tenth term in the following geometric sequence. 8, 4, 2, 1, . . .
Marrrta [24]

Answer:

  c)  0.0156

Step-by-step explanation:

The general term a[n] of a geometric sequence is given in terms of the first term a[1] and common ratio r as ...

  a[n] = a[1]r^(n-1)

The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...

  a[n] = 8(1/2)^(n-1)

The 10th term is then ...

  a[10] = 8(1/2)^(10-1) = 8(1/2)^9 = 8/512

  a[10] = 0.015625 ≈ 0.0156

7 0
3 years ago
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