The volume of a cone is 1/3 pi r^2 h, so plug this in to get the answer
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for

is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of

is always positive for

. That means at

there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function

is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer: 0.0791
Step-by-step explanation:
Given : The probability that a baseball player will get a hit in any one at bat is 0.250.
Let x be the first hit.
According to the geometric probability , the probability that x (th) trial is the first success =
, where p is the probability of getting success in each trial.
As per given p= 0.250
Then, the probability that he will get his first hit on his 5th at bat will be :

Hence, the probability that he will get his first hit on his 5th at bat is 0.0791 .
Answer: The answer is cosine of that acute angle.
Step-by-step explanation: We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.
In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.
Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.
Now, the ratio is given by

Thus, the ratio is cosine of the acute angle.