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iVinArrow [24]
3 years ago
10

Please help asap 40 pts

Mathematics
2 answers:
ch4aika [34]3 years ago
6 0
73.32. ft/sec is the correct answer




good luck

Korolek [52]3 years ago
3 0
v=\sqrt{64h}=\sqrt{64}\cdot\sqrt{h}=8\sqrt{h}\\\\h=84\ ft.\\\\substitute\\\\v=8\sqrt{84}\approx8\cdot9.1651\approx73.32

Answer:\ 73.32\ ft/sec

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the numbers 2-12 are written on cards and placed in the bag.what is the probability of picking an even number then replacing it
lorasvet [3.4K]

We have the cards numbered as 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.

Sample number is, n(S)=11.

We pick a card and want to get even number like 2, 4, 6, 8, 10, and 12.

Probability of picking an even number would be :-

P(even numbers) = \frac{6}{11}

Now we replace the card and want to get a 7 in second attempt.

Probability of picking a 7 would be :-

P(number 7) = \frac{1}{11}

Now Probability of this event = P(even numbers) × P(number 7)

Probability = (\frac{6}{11} )(\frac{1}{11} ) = \frac{6}{121}

So final answer is \frac{6}{121}.

3 0
3 years ago
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madam [21]
24 cubic units for blank 1
7 0
3 years ago
A rectangle has a height of k2 + 3 and a width of k2 + 7.
ElenaW [278]

Answer:

The area of the rectangle in polynomial form is k^4 +10 k^2 + 21

Step-by-step explanation:

Given

Shape: Rectangle

Height: k^2 + 3

Width: k^2 + 7

Required

Area of the rectangle

The area of a rectangle is calculated as thus;

Area = Length * Width

By substituting k^2 + 3 for height and k^2 + 7 for width; This gives

Area = (k^2 + 3)(k^2 + 7)

Expand the bracket

Area = k^2(k^2 + 7) + 3(k^2 + 7)

Open each bracket

Area = k^2*k^2 + k^2*7 + 3*k^2 + 3*7

Area = k^4 +7 k^2 + 3k^2 + 21

Area = k^4 +10 k^2 + 21

Hence, the area of the rectangle in polynomial form is k^4 +10 k^2 + 21

5 0
3 years ago
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Ivahew [28]
Fish tank A
V = Ah = 25 ft^2 * 8 ft = 200 ft^3

Fish tank B
V = Ah = 40 ft^2 * 4 ft = 160 ft^3

The volume of fish tank A is 200 ft^3, and the volume of fish tank B is 160 ft^3, so fish tank A has a greater volume. Its volume is greater by 40 ft^3.
4 0
3 years ago
(please help quickly find the greatest common factor of the following numbers ​
olasank [31]

Answer:

1a. 4

1b. 10

2a. 12

2b. 15

3a. 6

3b. 14

4a. 14

4b. 5

4 0
3 years ago
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