Question

During a game, the pittsburgh steelers converted 6 of 10 fourths downs into first downs. With only minutes left in the game, it is fourth down again and they must make a first down to continue their drive. What is the probability that they will make the first down?

Answer 1

Answer:

$\dfrac{3}{5}$

Step-by-step explanation:

Given that:

Total Number of fourth downs = 10

Number of fourth downs converted to first downs = 6

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, Let E be the event of getting a fourth down converted to first down.

So, Number of favorable cases = 6

Total Number of cases = 10

Therefore, the required probability is:

$P(E) = \dfrac{6}{10} = \dfrac{3}{5}$