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3 years ago

Make me your friend and i will mark brainliest and also what is 500^2-40^3/4

Mathematics

2 answers:

gregori [183]3 years ago

7 0

Answer:

234,000

Step-by-step explanation:

Is this a scam?

Oh no, it's a bribe. Yup. It was a bribe.

kolezko [41]3 years ago

6 0

Answer:

<h3>About 2484.1</h3>

Step-by-step explanation:

Just solve both step by step and then simplify, calculator might do wrong order of operation so be careful there

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Solve for x. 25 - 3x = -5(1 - x) - 2x

grandymaker [24]

Answer:

$x = 5$

Step-by-step explanation:

25 - 3x = -5(1 - x) - 2x

We have to first get rid of the parenthesis:

$-5 * 1$ ==> -5

$-5 * -x$ ==> 5x

So now you should have:

25 - 3x = -5 + 5x - 2x

Combine like terms:

25 - 3x = -5 + 5x - 2x

25 - 3x = -5 + 3x

Add 3x to both sides:

25 - 3x = -5 + 3x

+ 3x = + 3x

And you should have:

25 = -5 + 6x

Add 5 to both sides:

25 = -5 + 6x

+5 = +5

30 = 6x

Divide 6 to both sides:

$\frac{30}{6}$ = $\frac{6x}{6}$

5 = x

3 0

3 years ago

Read 2 more answers

A cell splits in half every 15 minutes. How many cells will there be in 150 minutes (2.5 hours)??

Trava [24]

The answer will be 2^10 or 1024 cells

5 0

4 years ago

1. What is the term given to the perimeter around a circle?

grigory [225]

The circumference and
Abacus

7 0

3 years ago

Read 2 more answers

A 25-foot long ladder is propped against a wall at an angle of 18° with the wall. how high up the wall does the ladder reach? ro

Alecsey [184]

Answer

Find out the how high up the wall does the ladder reach .

To proof

let us assume that the height of the wall be x .

As given

A 25-foot long ladder is propped against a wall at an angle of 18° .

as shown in the diagram given below

By using the trignometric identity

$cos\theta = \frac{Base}{Hypotenuse}$

now

$\theta = 18^{\circ}$

Base = wall height = x

Hypotenuse = 25 foot

Put in the trignometric identity

$cos18^{\circ} = \frac{x}{25}$

$cos18^{\circ} = \bar{0.9510565162}$

x = 23.8 foot ( approx)

Therefore the height of the ladder be 23.8 foot ( approx) .

8 0

3 years ago

Read 2 more answers

[25 POINTS] The approximate change in the value of f(x) = sqrt(2(x-1)) at x = 3 using differentials with dx = 0.01 is

otez555 [7]

Answer:

$\frac{1}{200}$

Step-by-step explanation:

Find the derivative of the function when x=3

$y=\sqrt{2(x-1)}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(x-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(3-1)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{2(2)}}$

$\frac{dy}{dx}=\frac{1}{\sqrt{4}}$

$\frac{dy}{dx}=\frac{1}{2}$

Since the change in the value of the function is $dy$ and we know that the change in x is $dx=0.01$ , then we have:

$\frac{dy}{dx}=\frac{1}{2}$

$dy=\frac{1}{2}dx$

$dy=\frac{1}{2}(0.01)$

$dy=\frac{1}{200}$

Therefore, the 2nd option is correct

8 0

2 years ago