Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative
3. E is at 2, 4. 1.67 −1.33 0.75 −1.25
2 answers:
I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.
You might be interested in
Answer:
r = 5 feet
Step-by-step explanation:
see attached for reference
recall that volume of a circular cone is given by
V = (1/3) πr²h, where
V = volume = given as 50π ft³
r = radius (we are asked to find this)
h = height of cone = given as 6 feet
Substituting the above known values into the equation:
V = (1/3) πr²h
50π = (1/3) π (r²)(6)
50π = π (r²)(2) (divide both sides by 2)
25π = π r² (divide both sides by π)
25 = r²
r = ±√25
r = ±5 (since radius cannot be negative, we select the positive value
r = 5 feet
