Question

Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative 3. E is at 2, 4. 1.67 −1.33 0.75 −1.25

Answer 1

I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.

Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.

Answer 2

The correct answer would be D.) -1.25. I will provide a picture of the original graph from the question for reference. I hope this helps you!