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o-na [289]
3 years ago
12

The blue figure is reflected over the y-axis and then rotated 270° counterclockwise around the origin. In which quadrant will th

e image be located?
Mathematics
1 answer:
kakasveta [241]3 years ago
4 0

Answer:

Step-by-step explanation:

The image will be in Quadrant IV.

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Follow the steps to find the value of x 1/5(x)5/1=6/3(5/1)
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Answer: x=10

This is the answer I got.

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The domain of F(x) = logo x is the set of all real numbers. <br><br> A True <br><br> B False
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Step-by-step explanation:

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The formula for the volume of a cube is V(s) = s3 where s is the side length of the cube. In which quadrant(s) is the graph of t
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If using the method of completing the square to solve the quadratic equation x2 −4x+13=0, which number would have to be added to
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2 years ago
Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *
Luda [366]

Answer:

The answer to your question is   \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1          

Step-by-step explanation:

Data

Foci  (-2, 2)  (4, 2)

Major axis = 10

Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

                  2c = 6

                    c = 6/2

                    c = 3

3.- Determine a

                  2a = 10

                    a = 10/2

                    a = 5

4.- Determine b using the Pythagorean theorem

                   a² = b² + c²

-Solve for b

                   b² = a² - c²

                   b² = 5² - 3²

                   b² = 25 - 9

                   b² = 16

                   b = 4

5.- Find the center (1, 2)  From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

                      \frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1

                       \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1                

3 0
2 years ago
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