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Alinara [238K]
3 years ago
8

Can someone plz help me I’m being timed!!

Mathematics
2 answers:
Whitepunk [10]3 years ago
6 0

Answer:

25

I hope i got it in time :)

jek_recluse [69]3 years ago
4 0

Answer:

25

Step-by-step explanation:

your subtracting 2 every time so you subtract 2 from 27 which is 25

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Hello , how to do 6(iii)?
Doss [256]

Answer:

\displaystyle \frac{dS}{dt}=\frac{3}{50r}

Step-by-step explanation:

Water is being pumped into an inflated rubber sphere at a constant rate of 0.03 cubic meters per second.

So, dV/dt = 0.03.

We want to show that dS/dt is directly proportional to 1/r.

In other words, we want to establish the relationship that dS/dt  = k(1/r), where k is some constant.

First, the volume of a sphere V is given by:

\displaystyle V=\frac{4}{3}\pi r^3

Therefore:

\displaystyle \frac{dV}{dt}=4\pi r^2\frac{dr}{dt}

Next, the surface area of a sphere S is given by:

\displaystyle S=4\pi r^2

Therefore:

\displaystyle \frac{dS}{dt}=8\pi r\frac{dr}{dt}

We can divide both sides by 2:

\displaystyle \frac{1}{2}\frac{dS}{dt}=4\pi r\frac{dr}{dt}

We can substitute this into dV/dt. Rewriting:

\displaystyle \frac{dV}{dt}=r\Big(4\pi r\frac{dr}{dt}\Big)

So:

\displaystyle \frac{dV}{dt}=\frac{1}{2}r\frac{dS}{dt}

Since dV/dt = 0.03 or 3/100:

\displaystyle \frac{3}{100}=\frac{1}{2}r\frac{dS}{dt}

Therefore:

\displaystyle \frac{dS}{dt}=\frac{3}{50r}=\frac{3}{50}\Big(\frac{1}{r}\Big)

Where k = 3/50.

And we have shown that dS/dt is directly proportional to 1/r.

4 0
3 years ago
A rectangular bin with an open top and volume of 38.72 cubic feet is to be built. The length of its base must be twice the width
KengaRu [80]

Answer:

Width=2.2 FT

Length=4.4 FT

Heigh= 4 FT

Step-by-step explanation:

5 0
3 years ago
X^2+6x+3=0<br><br> Solve the equation by completing the square
tester [92]

Answer:

Step-by-step explanation:

UKOAAAAAAKUPAAAAIJUFRHFUEHDEUEDHUDEHUSDHJUGIJUJGIJUGIJGUGJGIJGIGOOOOOOUUUIVJRIJIJRF

8 0
3 years ago
Please help! Thank you
Temka [501]

Answer:

b. the radio of feet to inches

4 0
3 years ago
Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2
valentina_108 [34]

Answer:

Solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

Step-by-step explanation:

We need to solve the equation x^2+6x-8=0 by completing the square method.

For completing the square method: we need to follow: a^2+2ab+b^2=(a+b)^2

We are given:

x^2+6x-8=0

Solving by completing the square

x^2+2(x)(?)+(?)^2-8=0

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17

So, solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

7 0
3 years ago
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