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IgorC [24]
3 years ago
10

A box contains 10 tags, numbered 1 through 10, with a different number on each tag. A second box contains 8 tags, numbered 20 th

rough 27, with a different number on each tag. One tag is drawn at random from each box. What is the expected value of the sum of the numbers on the two selected tags(A) 13.5(B) 14.5(C) 15.0(D) 27.0(E) 29.0
Mathematics
1 answer:
blagie [28]3 years ago
3 0

Answer:

E) 29.0

Step-by-step explanation:

The value of the sum is obtained from 2 independent experiments: the value of the number of the first box X₁ and the value of the number of the second box X₂.

The expected value of a draw is the average of all its values, so E(X₁) = (1+2+3+4+5+6+7+8+9+10)/10 = 5.5 and E(X₂) = (20+21+22+23+24+25+26+27)/8 = 23.5

Hence, E(X₁+X₂) = E(X₁)+E(X₂) = 5.5+23.5=29

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VikaD [51]

Answer:

3) 5

4) 8.2

5) 6.8

6)FG = 6.4

7) EF = 3.6

8)DF = 4.8

Step-by-step explanation:

From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)

Thus, ∠G = 36.87°

Still using trigonometric ratios;

FG/8 = cos 36.87°

FG = 8 cos 36.87°

FG = 6.4

3) EF + FG = EG

Since EG is 10, mean of EF and FG = 10/2 = 5

4) mean of EG and FG = (10 + 6.4)/2 = 8.2

5) EF + FG = EG

Thus; EF = EG - FG

EF = 10 - 6.4

EF = 3.6

Mean of EG and EF = (10 + 3.6)/2 = 6.8

6) FG = 6.4

7) EF = 3.6

8) Using trigonometric ratio;

DF/8 = sin 36.87

DF = 8 × 0.6

DF = 4.8

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2 years ago
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anastassius [24]

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Step-by-step explanation:

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Step-by-step explanation:

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