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ra1l [238]
2 years ago
5

-7/10 divided by 2/5 in it's simplest form

Mathematics
1 answer:
sergey [27]2 years ago
5 0
The answer is -1 and 3/4
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Find the distance between the points (1,8) and (9, 2).
grin007 [14]

Answer:

distance = \sqrt{(x_{1} -x_{2})^2+(y_{1} -y_{2})^2  }\\\\

             =\sqrt{(9-1)^2+(2-8)^2  }\\\\=\sqrt{8^2 + 6^2}\\\\=\sqrt{64 +36 }\\\\=\sqrt{100} = 10units

6 0
3 years ago
First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

7 0
2 years ago
Need help please?!?!?! Extra points!!!
andrey2020 [161]

Answer:

4.19

Step-by-step explanation:

just use the formula 2pir^2

8 0
3 years ago
Find the ordered pairs for x and y intercepts of the equation 3x - 2y =18
My name is Ann [436]
                  
                                                           3x - 2y = 18
Wherever the line crosses the
x-axis, y=0.                                         3x        = 18
                                                             x        =  6
The x-intercept is                                    (6, 0)  .


                                                           3x - 2y = 18
Wherever the line crosses the
y-axis,  x=0.                                            - 2y = 18
                                                                   y = -9
The y-intercept is                                        (0, -9)  .

8 0
3 years ago
Read 2 more answers
Y + 3=-(x +5) match the graph with the correct equation
adelina 88 [10]
Simplified firstly ,y = -x-8,
and then make two point,(-8.0)(0.-8),line them.finish.if u wanna get more details,tell me
6 0
3 years ago
Read 2 more answers
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