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3 years ago

What is 4 common multiples of 2 and 4

Mathematics

1 answer:

ivann1987 [24]3 years ago

4 0

Answer:

Multiples of 2 are {2,4,6,8,10,12,14,16,...} Multiples of 4 are {4,8,12,16,.......) Hence common multiples are {4,8,12,16,...} and Lowest Common Multiple is 4 .

Step-by-step explanation:

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iren2701 [21]

Answer:

Step-by-step explanation:

B) Small triangle:

height = 20 - 15 = 5

base = 1

height to base = 5 :1

Medium triangle :

height = 60 -30 = 30

base = 2

height to base = 30 :2 = 15 :1

Large triangle:

height = 120 - 60 = 60

base = 4

height to base = 60 : 4 = 15 : 1

c) The ratios are same. This is true because wage and working hours are in direct proportion.

E) Take any two points. (1 , 15) & (2 , 30). Find the slope.

Slope = Change in y ÷ change in x

m = (30-15) ÷ (2 -1) = 15/1 = 15

y -y1 = m(x -x1)

y - 15 = 15(x - 1)

y - 15 = 15x - 15

y = 15x - 15 + 15

y = 15x

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3 years ago

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frosja888 [35]

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What is the value of a in this linear system?

Sergio [31]

Answer:

Step-by-step explanation:

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3 years ago

If the two factors (below, not the picture tho) 6 and 10,000,000 make 60,000,000 what is the second factor is the equation?

Pachacha [2.7K]

Answer:

It's 6 to the power of 7

Step-by-step explanation:

60,000,000

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3 years ago

The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit

wolverine [178]

Answer:

(a) $\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

$P(t)=\frac{240t-40t^2}{t^2+20}$

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

$P(t)=\frac{240t-40t^2}{t^2+20}$ using quotient rule.

$\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}$

Simplifying

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

$P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}$

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

$P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}$

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

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3 years ago