d = 3 , a₁₂ = 40 and S
= 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a

= a₁ + (n-1)d</h3><h3>• S

=

[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =

[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer:

Step-by-step explanation:
<u>Density</u>
The density of an object of mass m and volume V is given by

It can be expressed in common units like
or any other combination of proper mass [M] by volume [V] units.
The data provided in the question is


Thus, the measured density is


We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.
The side length is the cube root of 460.
cube root(460) = 460^(1/3)
That's approximately 7.7
Answer:
<h3>
(base)² + (altitude)² = (hypotenuse) ²</h3>
Therefore,
2²+5² = c² will be matched.
If 24 is a solutoin of x, n has to be 24 squared. 24*24=576