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Elan Coil [88]
3 years ago
12

You are at a family reunion and the cooler contains ten bottles of soda; four Sprite, three Dr. Pepper, and three Cherry Coke. T

hree times, you randomly pick up a drink for your grandmother. The first time, you get a Dr. Pepper. The second and third times, you get Cherry Coke. What is the probability of getting Dr. Pepper the fourth time and then an Dr. Pepper the fifth time without replacement?
Mathematics
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

<em></em>Probability = \frac{18}{1860480}<em></em>

<em></em>

Step-by-step explanation:

Given

Soda = 10

Sprite = 4

Dr. Pepper = 3

Cherry Coke = 3

Required

Determine the probability of picking Dr. pepper the fourth and fifth

First, we need to sum up the number of drinks

Total = 10 + 4 + 3 + 3

Total = 20

First Selection: Dr. Pepper

P_1= \frac{3}{20}

Since its probability without replacement;

<em>At this stage: Dr. Pepper = 2 and Total = 19</em>

Second Selection: Cherry Coke

P_2= \frac{3}{19}

<em>At this stage: Dr. Pepper = 2; Cherry Coke = 2 and Total = 18</em>

<em></em>

Third Selection: Cherry Coke

P_3= \frac{2}{18}

P_3= \frac{1}{9}

<em>At this stage: Dr. Pepper = 2; Cherry Coke = 1 and Total = 17</em>

<em></em>

Fourth Selection: Dr. Pepper

P_4= \frac{2}{17}

<em>At this stage: Dr. Pepper = 1; Cherry Coke = 1 and Total = 16</em>

<em></em>

Fifth Selection: Dr. Pepper

P_5= \frac{1}{16}

<em></em>

<em>Multiply the calculated probabilities, to give the required probability</em>

<em></em>Probability = P_1 * P_2 * P_3 * P_4 * P_5<em></em>

<em></em>Probability = \frac{3}{20} * \frac{3}{19} * \frac{1}{9} * \frac{2}{17} * \frac{1}{16}<em></em>

<em></em>Probability = \frac{3 * 3 * 1 * 2 * 1}{20 * 19 * 18 * 17 * 16}<em></em>

<em></em>Probability = \frac{18}{1860480}<em></em>

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