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nignag [31]
3 years ago
13

7. You purchased crackers for $2.79, a steak for $5.27. ice cream for

Mathematics
2 answers:
Paul [167]3 years ago
7 0

Answer:

A: yes

Step-by-step explanation:

It is reasonable because when we round each number, for example $2.79 to $2 , and add them together , it is about $19

bixtya [17]3 years ago
3 0

Answer:

no who pays almost 9 bucks for ice cream

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When x is 3, y is 15. If y varies directly as x, which equation relates x and y?
NARA [144]

Answer:

x5=y

Step-by-step explanation:

Let's say 3y=15

3 x 5 = 15, so y=5.

4 0
3 years ago
Use a graph to solve this equation.<br> th<br> 2x2–5=-X? + 2x – 1
solong [7]

Answer:

X + 2= 0

X - 4  > 7

-4 + y = 3y + 4 (y - 3)

4 0
3 years ago
Find the first three iterates of the function f(z)=z2+c with a value of c=1+2i and an initial value of z0=0
aalyn [17]

Answer:

14x

Step-by-step explanation:

multiply the 2i by the 0 eulogistic quotient

7 0
3 years ago
Read 2 more answers
What is the solution of this system of linear equations? 3y = 3 y equals StartFraction 3 over 2 EndFraction x plus 6.X + 6 y – S
Scrat [10]

Answer:

(0,6)

Step-by-step explanation:

The given system of equations is

y =  \frac{3}{2}x + 6

and

\frac{1}{2}y -  \frac{1}{4}x = 3

We substitute the first equation into the second equation to get:

\frac{1}{2} ( \frac{3}{2}x + 6) -  \frac{1}{4}x = 3

We expand to get:

\frac{3}{4} x + 3 -  \frac{1}{4}x = 3

We group similar terms to get:

\frac{3}{4}x -  \frac{1}{4}x = 3 - 3

\frac{1}{2}x = 0

x = 0

Put x=0 in to the first equation to get:

y = 6

Therefore the solution is (0,6)

3 0
3 years ago
Read 2 more answers
Ments
maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

A = \frac{\theta}{360} * \pi r^2 --- sector area

L = \frac{\theta}{360} * 2\pi r ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

A = \frac{\theta}{360} * \pi r^2

So, we have:

A = \frac{160}{360} * \frac{22}{7} * 5^2

Evaluate

A = 34.92

The arc length is:

L = \frac{\theta}{360} * 2\pi r

So, we have:

L = \frac{160}{360} * 2 * \frac{22}{7} * 5

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

#SPJ1

8 0
1 year ago
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